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3 years ago

7

During the first 6 weeks of the sports season, the cougars had won 4 games and lost 2 games. At this rate, how many games will t

hey win out of 24

1 answer:

serg [7]3 years ago

3 0

Answer: 16

Step-by-step explanation:

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A stack of 6 bricks is 2 feet high. How high is a stack of 20 bricks?

Korolek [52]

60.

The question gives you the fact that 6 bricks is 2 feet high.

What do you do to get from 2 to 20?
You multiply by 10.

Since you multiplied one thing by 10, you must do it to the other side so it remains balanced.

2 ft x 10ft = 20ft

6 bricks x 10 bricks = 60 bricks

8 0

3 years ago

Half a number increased by 15 is equal to the sum of 5 and the product of 3 and the number.

son4ous [18]

Answer:

(x/2) + 15 = 5 + 3x

Step-by-step explanation:

Follow the steps in the equation. X is your number. First you halve it, then you add 15. Next, set it equal to the other side. The second side is 5 + (because it is the sum) and 3x (the product of 3 and x means multiply them)

3 0

3 years ago

Help I will be marking brainliest!!

lora16 [44]

Answer:

<u>Given</u>: base = 10.4ft, height = 12.5

Area of octagon = 8(1/2 × b × h)

8(1/2 × 10.4 × 12.5)
520ft²

Volume of pool = 520ft² × 3ft

1560ft³

Now, 1 cubic ft takes 7.5 gallons to fill.

Therefore, 1560 cubic ft takes,

1560 × 7.5
11700

So, <u>Correct choice</u> - [D] 11,700.

5 0

3 years ago

Find the value of x:

nadya68 [22]

Answer:

x = 3

Step-by-step explanation:

These angles are vertical angles. Vertical angles equals to on another but on the opposite side. Since they equal to another you do:

(10x + 1) = (12x - 5)

Add 5 on both sides:

10x + 6 = 12x

Subtract 10x on both sides:

6 = 2x

Divide 2 on both sides:

3 = x

6 0

3 years ago

Read 2 more answers

Find the radius of convergence, r, of the series. ∞ xn 2n − 1 n = 1 r = 1 find the interval, i, of convergence of the series. (e

Bingel [31]

Assuming the series is

$\displaystyle\sum_{n\ge1}\frac{x^n}{2n-1}$

The series will converge if

$\displaystyle\lim_{n\to\infty}\left|\frac{\frac{x^{n+1}}{2(n+1)-1}}{\frac{x^n}{2n-1}}\right|$

We have

$\displaystyle\lim_{n\to\infty}\left|\frac{\frac{x^{n+1}}{2(n+1)-1}}{\frac{x^n}{2n-1}}\right|=|x|\lim_{n\to\infty}\frac{\frac1{2n+1}}{\frac1{2n-1}}=|x|-\lim_{n\to\infty}\frac{2n-1}{2n+1}=|x|$

So the series will certainly converge if $-1$ , but we also need to check the endpoints of the interval.

If $x=1$ , then the series is a scaled harmonic series, which we know diverges.

On the other hand, if $x=-1$ , by the alternating series test we can show that the series converges, since

$\left|\dfrac{(-1)^n}{2n-1}\right|=\dfrac1{2n-1}\to0$

and is strictly decreasing.

So, the interval of convergence for the series is $-1\le x$ .

6 0

3 years ago