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Reil [10]
2 years ago
11

What is the slope of the line?

Mathematics
2 answers:
ankoles [38]2 years ago
6 0
It is 4858833959694995.838485842829496959494596
Ahat [919]2 years ago
3 0

Answer:

Y= -4/-4x -1

Step-by-step explanation:

I think this is correct, I haven't done this in awhile though. I hope this helps

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In a competition between players X and Y, the first player to win three games in a row or a total of four games wins. How many w
OLEGan [10]

Answer:

The competition can be played in 7 different ways

Step-by-step explanation:

First game : X

Second game : Y

Third game : Y

After that either X or Y can win

<h3>¹Case - 1: Y wins the fourth game:</h3>

The competition ends with Y winning as he/she won 3 games in a row

<h3>Case - 2: X wins the fourth game:</h3>

more games are required to decide the winner

<h3>Sub-case - a: X wins the fifth game:</h3>

more games are required to decide the winner

<h3>²Sub-sub-case - i: X wins the sixth game:</h3>

The competition ends with X winning as he/she won 3 games in a row

<h3>³⁻⁴Sub-sub-case - ii: Y wins the sixth game:</h3>

The competition ends after the seventh game. Whoever wins seventh game wins the competition as he/she would've won 4 games in total by then.

<h3>Sub-case - b: Y wins the fifth game:</h3>

more games are required to decide the winner

<h3>⁵Sub-sub-case - i: Y wins the sixth game:</h3>

The competition ends with Y winning as he/she won 4 games in total

<h3>⁶⁻⁷Sub-sub-case - ii: X wins the sixth game:</h3>

The competition ends after the seventh game. Whoever wins seventh game wins the competition as he/she would've won 4 games in total by then.

∴<u>The competition can be played in 7 different ways</u>

7 0
3 years ago
Write an equation for the line that has a slope -8/9 and goes through the point (-7, 7)
Jobisdone [24]

Answer:

y = (-8/9)x + 0.77777

Step-by-step explanation:

We already know the slope, so the only thing left to find is the y-intercept.

To find the y-intercept, we can <u>plug in the slope and point to the slope-intercept form equation</u> (y = mx+b, where m=slope and b=y-int.)

y   =     m *  x    + b

(7) = (-8/9)*(-7)   + b

<u>Now, just solve for b!</u>

(7) = (-8/9)*(-7)   + b

7 = 56/9 + b

7 - (56/9) = b

b = 0.777777 (repeating decimal, usually signified by a little line above the 7)

so now we just <u>plug in the slope and y-intercept we found into y = mx + b.</u>

y = mx + b

y = (-8/9)x + 0.77777

5 0
2 years ago
Read 2 more answers
One card is randomly selected from a deck of cards. find the odds against drawing a blackblack fivefive.
neonofarm [45]
Since there are 2 black suites and there are 26 (1/2) black cards in a deck, and there is 1 five per suite, there are 2 black fives. Therefore, since there are 52 cards in a deck, there is a 2/52 you draw a black 5. To find the odds against that, we get 1-2/52=52/52-2/52=50/52 due to that we want to find the probability of not drawing a black 5 so we subtract the chances of getting that from the equation
6 0
3 years ago
What is y + 9 &lt; -6 ???
FrozenT [24]
Y is less than or equal to -16 i think but I’m not sure
4 0
2 years ago
Let f(x)= x(2x-3)/(x+2)x. Find the domain, vertical and horizontal asymptote
Reptile [31]

Step-by-step explanation:

Domain of a rational function is everywhere except where we set vertical asymptotes. or removable discontinues

Here, we have

\frac{x(2x - 3)}{(x + 2)x}

First, notice we have x in both the numerator and denomiator so we have a removable discounties at x.

Since, we don't want x to be 0,

We have a removable discontinuity at x=0

Now, we have

\frac{2x - 3}{x + 2}

We don't want the denomiator be zero because we can't divide by zero.

so

x + 2 = 0

x =  - 2

So our domain is

All Real Numbers except-2 and 0.

The vertical asymptors is x=-2.

To find the horinzontal asymptote, notice how the numerator and denomator have the same degree. So this mean we will have a horinzontal asymptoe of

The leading coeffixent of the numerator/ the leading coefficent of the denomiator.

So that becomes

\frac{2}{1}  = 2

So we have a horinzontal asymptofe of 2

7 0
2 years ago
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