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EastWind [94]
3 years ago
13

PLEASE HELP NOW!!

Mathematics
1 answer:
Rufina [12.5K]3 years ago
7 0

1. Carl's constant rate of speed is the slope of the straight line graph.

This straight line passes through: (0,0), (5,1), (10,2) etc

We can use the slope formula with any two points to find the slope of this line.

The slope formula is m=\frac{y_2-y_1}{x_2-x_1}.

Let (x_1,y_1)=(0,0) and (x_2,y_2)=(5,1)

Then m=\frac{1-0}{5-0}, \implies m=\frac{1}{5}.

Carl's speed is \frac{1}{5} miles per minute.

But we must leave our answer in miles per hour

Hence Carl's speed is \frac{1}{5}\times 60=12  miles per hour

After 2 hours, Carl will travel 12\times 2=24 miles.

2. The given line has equation -4x+y=10

We write this in slope-intercept form by solving for y.

\implies y=4x+10

This is in the form y=mx+c, where m=4 is the slope.

When x=3,  y=4(3)+10

\implies y=12+10=22

When x=3, y=22

3. The given straight line graph that models the situation passes through:

(0,0) and (20,30).

The slope of this line is \frac{Rise}{Run}=\frac{300}{20}=15

Therefore the rate is $ 15 per ticket.

If the theater sells 150 tickets, the earnings will be: 150\times 15=2,250 dollars.

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Which number line can be used to find the distance between (-1, 2) and (-5, 2)
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Answer:

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Step-by-step explanation:

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Which is 4 units

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Denise has a stool with a circle seat on top. The diameter of the seat is 14inches, and she wants to know the area of the top in
saul85 [17]

Answer:21?

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3 years ago
A particle begins at point (1, 2) and is moving along the line segment joining (1, 2) to (3, 4). Initially, what is the rate of
Bumek [7]

Answer:

Initially, that is, at (1,2), the rate of increase of the function in the direction given = 0

Hence the function is neither increasing nor decreasing initially in the given direction.

Step-by-step explanation:

f(x,y) = 2x² - y²

Rate of Change of the function = ∇f = (fₓ, fᵧ)

And we're told to find the rate of change in a particular direction = ∇f.û

We first obtain the unit vector in that direction, û

Direction = (3,4) - (1,2) = (2,2)

Uni vector = vector/magnitude

Vector = 2î + 2j

magnitude = √(2² + 2²) = √8 = 2 √2

(2î + 2j)/(2√2) = (1/√2)î + (1/√2)j = û

Unit vector in the direction = (1/√2, 1/√2)

f = 2x² - y²

At (1,2)

fₓ = ∂f/∂x = 4x = 4

fᵧ = ∂f/∂y = -2y = -4

∇f = (4,-4)

∇f.û = (4î - 4j).((1/√2)î + (1/√2)j) = (4/√2) - (4/√2) = 0

If it was positive, then the function is increasing, if it was negative, the function is decreasing. Zero means neither of them.

Hence the function is neither increasing nor decreasing initially in the given direction.

7 0
3 years ago
Sally launches a rocket off of a platform. The height of the rocket, in meters, can be modeled by the function, h(x) = -5(x - 3)
Lorico [155]

Answer:

Time = 3secs

Max height = 56m

Step-by-step explanation:

Given the height reached by the rocket modeled by the equation;

h(x) = -5(x - 3)² + 56 where;

x is in seconds

The rocket velocity at its maximum height is zero.

Hence dh/dx = 0

dh/dx = 2(-5)(x-3)

dh/dx = -10(x-3)

Since dh/dx = 0

0 = -10(x-3)

0 = -10x + 30

10x = 30

x = 3secs

<em>Hence it takes 3 secs to reach the maximum height.</em>

Get the maximum height reached by the rocket. Substitute x = 3 into the equation given;

Recall that:

h(x) = -5(x - 3)² + 56

If x  = 3

h(3) = -5(3 - 3)² + 56

h(3) = 0 + 56

h(3) = 56

<em>Hence the maximum height that the rocket reaches is 56m</em>

4 0
3 years ago
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