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natali 33 [55]
3 years ago
12

What is y=3x squared in standard form so I can graph it as a quadratic function

Mathematics
1 answer:
maria [59]3 years ago
4 0

the standard form of a quadratic is simply the equation with all variables and constant on the left-hand-side.


y = 3x² <--- general form

-3x² + y = 0 <--- standard form.

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Find the values of x and y that make these triangles congruent by the HL Theorem.
RideAnS [48]

According to HL theorem if one leg and hypotenuse of one right triangle are equal to one leg and hypotenuse of other right triangle, then the triangles are congruent.

By using this theorem we can set up the system of equations as follows:

x=y+1 ...(1)

2x+3= 3y + 3 ..(2)

By using equation (1) next step is to plug in y+1 for x in equation (2). So,

2 ( y + 1) + 3 = 3y + 3

2y + 2 + 3 = 3y + 3 By using distribution property.

2y + 5 = 3y + 3

2y + 5 - 5 = 3y + 3 - 5 Subtract 5 from each side.

2y = 3y - 2

2y - 3y = -2 Subtract 3y from each sides.

-y = -2

So, y=2

Next step is to plug in y=2 in equation (1) to get the value of x. Hence,

x= 2+1

=3

So, x=3 and y=2 make these triangles congruent.

So, the correct choice is 3. x = 3, y = 2.

7 0
3 years ago
13) -4= -b -1/3b and -23/3= 1/2a + 5/3a
Sergeeva-Olga [200]

-4=-1b-(1/3)b

-4=-(4/3)b

-4/-(4/3)=b

b=3

-------------------------------

(1/2)3+(5/3)2

3/6+10/6=13/6

-23/3=13/6a

(-23/3)/(13/6)=a

a=-46/13

7 0
3 years ago
A body moves s metres in a time t seconds so that s = t3 – 3t2 + 8. Find:
Lady bird [3.3K]

Using derivatives, it is found that:

i) v(t) = 3t^2 - 6t

ii) 9 m/s.

iii) a(t) = 6t - 6

iv) 6 m/s².

v) 1 second.

<h3>What is the role of derivatives in the relation between acceleration, velocity and position?</h3>
  • The velocity is the derivative of the position.
  • The acceleration is the derivative of the velocity.

In this problem, the position is:

s(t) = t^3 - 3t^2 + 8

item i:

Velocity is the <u>derivative of the position</u>, hence:

v(t) = 3t^2 - 6t

Item ii:

v(3) = 3(3)^2 - 6(3) = 27 - 18 = 9

The speed is of 9 m/s.

Item iii:

Derivative of the velocity, hence:

a(t) = 6t - 6

Item iv:

a(2) = 6(2) - 6 = 6

The acceleration is of 6 m/s².

Item v:

t for which a(t) = 0, hence:

6t - 6 = 0

6t = 6

t = \frac{6}{6}

t = 1

Hence 1 second.

You can learn more about derivatives at brainly.com/question/14800626

7 0
2 years ago
Solve for x Rount to the nearest tenth if necessary
bulgar [2K]

Answer:

20.7

Step-by-step explanation:

7 0
2 years ago
Find the sum and difference (first mixed number minus the second mixed number) for the following pair of mixed numbers. The answ
xz_007 [3.2K]

Answer:

Sum = 15 8/15, Difference = 1 2/15

Step-by-step explanation:

8⅓, 71/5

A. Sum

8⅓ + 7 1/5

Convert to improper fraction

25/3 + 36/5

Find the LCM of 3 and 5. The result is 15. Divide 15 by the denominator of each fraction and multiply the result obtained with the numerator. The result is shown below:

[(25×5) + (36×3)] / 15

[125 + 108] / 15

233 / 15

Convert to mixed fraction

15 8/15

B. Difference

8⅓ – 7 1/5

Convert to improper fraction

25/3 – 36/5

Find the LCM of 3 and 5. The result is 15. Divide 15 by the denominator of each fraction and multiply the result obtained with the numerator. The result is shown below:

[(25×5) – (36×3)] / 15

[125 – 108] / 15

17 / 15

Convert to mixed fraction

1 2/15

SUMMARY:

Sum = 15 8/15, Difference = 1 2/15

3 0
3 years ago
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