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Minchanka [31]
3 years ago
6

Cystic fibrosis is a genetic disorder in homozygous recessives that causes death during the teenage years. If 9 in 10,000 newbor

n babies have the disease,
what are the expected frequencies of the dominant (A1) and recessive (A2) alleles according to the Hardy-Weinberg equation?
(a) f(A1) = 0.9997, f(A2) = 0.0003(b) f(A1) = 0.9800, f(A2) = 0.0200(c) f(A1) = 0.9700, f(A2) = 0.0300(d) f(A1) = 0.9604, f(A2) = 0.0392
Biology
1 answer:
padilas [110]3 years ago
5 0

Answer:

f(A1) = 0.9700, f(A2) = 0.0300

Explanation:

The frequency of homozygous recessive genotype of children is  

\frac{9}{10000} \\= 0.0009

As per Hardy weinberg's equation, frequency of homozygous recessive genotype is represented by  

q^2

Here q^2 = 0.0009

Thus, frequency of recessive allele would be  

\sqrt{q^2}\\ = \sqrt{0.0009}\\ = 0.03

as per first law of Hardy weinberg

p+q = 1\\p = 1- 0.03\\p = 0.97

Hence, option C is correct

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kirill115 [55]

Commensalism relationship is shown between cattle egret and cattle.

Usually cattle egrets follow herds of large hoofed mammals such as cattle, buffalo. They eat the insects that have been stirred up by the buffalo as they move. This relationship is commensalism, because the birds benefit but the ungulate is neither harmed nor helped.

The cattle egret and grazing cattle in a close association is a classic example of commensalism. It is a common sight in rural areas where one can see ticks hovering over the cattle. They feed on cattle's blood and hence are harmful to them as they can transmit several diseases. The cattle egret and grazing cattle in a close association is a classic example of commensalism. It is a common sight in rural areas where one can see ticks hovering over the cattle. They feed on cattle's blood and hence are harmful to them as they can transmit several diseases.

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8 0
2 years ago
You have a 15kb plasmid. EcoRI cuts the plasmid into 7kb and 8kb pieces, and BamHI cuts the plasmid into 1kb and 14kb pieces. If
Harman [31]

Answer:

a. Bands at 1kb, 6kb and 8kb

Explanation:

The EcoRI and BamHI are the restriction enzymes which cut the DNA sequence especially a plasmid at specific sites called the restriction sites.

The restriction enzymes produces bands of specific length therefore these restriction enzymes are used to estimate the approximate length of the DNA.

In the given question, the

1. EcoRI- produces two strands of 7 kb and 8 kb

2. BamHI- produces two strands of 1kb and 14kb

This shows that the length of DNA sequence is 15kb

But when the DNA strand are digested with both the enzymes simultaneously then it will produce three bands as:

i) 14 kb can be broken down in 2 bands of 6 kb and 8 kb

ii) 1 kb band is already produced by the Bam HI.

This shows that 1+6+8= 15 kb

Thus, Option-A is correct.

5 0
3 years ago
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Answer:

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Sorry If I misspell or have horrible grammar

Explanation :

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Edit : Also I tried to put the answer I found into my own words , I noticed the 1st person copied and pasted an answer which is copying

3 0
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