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3 years ago

11

What does x equal in the equation 2x + y - 3z equals -12

1 answer:

lidiya [134]3 years ago

8 0

2x+y-3z=12

2x=4z-y

x=2z-y/2

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If 3x-y=123x−y=123, x, minus, y, equals, 12, what is the value of \dfrac{8^x}{2^y} 2 y 8 x start fraction, 8, start superscrip

julia-pushkina [17]

Answer:

$2^{12}=4,096$

Step-by-step explanation:

You know that $3x-y=12$ and have to find

$\dfrac{8^x}{2^y}$

Use the main properties of exponents:

1. $(a^m)^n=a^{m\cdot n}$

2. $\dfrac{a^m}{a^n}=a^{m-n}$

Note that

$8=2^3,$

then

$7^x=(2^3)^x=2^{3\cdot x}=2^{3x}$

Now

$\dfrac{8^x}{2^y}=\dfrac{2^{3x}}{2^y}=2^{3x-y}$

Since $3x-y=12,$ then $2^{3x-y}=2^{12}=4,096$

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3 years ago

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zvonat [6]

The solutions are $x=15, x=-8$ and $x=9$

Explanation:

Part a: The equation is $\frac{1}{3} (5x-9)=2(\frac{1}{3} x+6)$

Let us find the value of x.

Multiply the terms within the bracket, we get,

$\frac{5}{3} x-3=\frac{2}{3} x+12$

Subtracting both sides by $\frac{2}{3} x$ , we have,

$\frac{3}{3} x-3=12$

Adding both sides by 3,

$x=15$

Thus, the solution of the equation $\frac{1}{3} (5x-9)=2(\frac{1}{3} x+6)$ is $x=15$

Part b: The equation is $4(3x+5)-3=9x-7$

Multiply the terms within the bracket, we get,

$12x+20-3=9x-7$

Subtracting both sides by 9x, we have,

$3x+17=-7$

Subtracting both sides by 17,

$3x=-24$

Dividing both sides by 3, we have,

$x=-8$

Thus, the solution of the equation $4(3x+5)-3=9x-7$ is $x=-8$

Part c: The equation is $5(x+7)-3(x-4)=7x+2$

Multiply the terms within the bracket, we get,

$5x+35-3x+12=7x+2$

Adding the like terms, we have,

$2x+47=7x+2$

Subtracting both sides by 2 and 2x, we get,

$45=5x$

Dividing both sides by 5, we have,

$x=9$

Thus, the solution of the equation $5(x+7)-3(x-4)=7x+2$ is $x=9$

8 0

4 years ago