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mel-nik [20]
4 years ago
15

Find five rational numbers between 2/3and4/5​

Mathematics
2 answers:
daser333 [38]4 years ago
8 0

Answer:

31/45, 32/45, 11/15, 34/35, 7/9.

Step-by-step explanation:

The LCM of 3 and 5 is 15 so we can write 2/3 and 4/5 as:

10/15 and  12/15 so one rational number between these is 11/15.

Now 11/15 = 33/45 and 4/5 = 36/45

So 2 rationals between these are 34/45 and 35/45 = 7/9

2/3 = 30 /45 and 11/15 = 33/45

so  2 rationals between these are 31/45 and 32/45.

alexdok [17]4 years ago
7 0

Answer:

61 / 90, 62 /90, 63 /90, 64/90, 65/90

Explanation:

2/3 = 2 x 5 / 3  x 5 

       = 10 / 15 

4/5 = 4 x 3 / 5 x 3 

       12 / 15 

we can find 5 rational numbers betwen 2/3 and 4/5 by multiplying them with 5 + 1 = 6 

10 / 15  X 6 /6 

= 60 / 90 

12/ 15 X 6 /6 

= 72 / 90 

the rational numbers = 61 / 90  62 /90  63 /90  64/90  65/90  

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stepladder [879]

Answer:

slope= - 3/4

A(-4,3) and B(4,-3)

slope=m=\frac{y_B-y_A}{x_B-x_A} =\frac{-3-3}{4-(-4)} =\frac{-6}{8} =-\frac{3}{4}

3 0
4 years ago
Drag the correct steps into order to solve the equation −4x+12=−4 for x.
fiasKO [112]

The next step in this problem would be to subtract 12 form both sides. This would result in:

-4x = - 16

Then you would divide each side by -4.

x = 4

This would be your answer.

5 0
3 years ago
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Answer the following equations:
Andrew [12]

Step-by-step explanation:

3(t+5) = 9

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3t = -6

t = -2

2(f-7) = -10

2f - 14 = -10

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f = 2

-(c - 9) = 4

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c = 5

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12t = 36

t = 3

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s = 3.7

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7 = (F - 32)/9

By cross multiplication,

63 = F - 32

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<em>Hope</em><em> </em><em>it</em><em> </em><em>helps</em><em>.</em>

7 0
2 years ago
2). Jacob is buying ice cream. How many combinations are there?
jeka94
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Hope this helps!! :)
8 0
3 years ago
How do you solve this absolute value equation and inequality problem?
blsea [12.9K]

Answer:

r < -7 or r > 10

Step-by-step explanation:

-2|3 - 2r| < -34

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Now we split it up into 2 inequalities :-

3 - 2r > 17

-2r > 14

r  < -7     (answer)

and

3 - 2r < -17

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r > 10  (answer).

4 0
3 years ago
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