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2 years ago

36 is 18% of what number?

Mathematics

2 answers:

Alex_Xolod [135]2 years ago

8 0

Answer: 200

Step-by-step explanation: 36 by 100 and then divide the total by 18 as follows: (36 x 100) / 18 For 200

Alex Ar [27]2 years ago

6 0

Answer:

200

Step-by-step explanation:

I hope

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Please Help Me!!!!!!!

Ghella [55]

Answer:

Step-by-step explanation:

(6, 24) this ordered pair has an x-value of 6 and a y-value of 24

The only equation, if you substitute those values into it, which works is D.

24 = 4(6)

24 = 24

6 0

3 years ago

For a certain river, suppose the drought length Y is the number of consecutive time intervals in which the water supply remains

AnnZ [28]

Answer:

a) There is a 9% probability that a drought lasts exactly 3 intervals.

There is an 85.5% probability that a drought lasts at most 3 intervals.

b)There is a 14.5% probability that the length of a drought exceeds its mean value by at least one standard deviation

Step-by-step explanation:

The geometric distribution is the number of failures expected before you get a success in a series of Bernoulli trials.

It has the following probability density formula:

$f(x) = (1-p)^{x}p$

In which p is the probability of a success.

The mean of the geometric distribution is given by the following formula:

$\mu = \frac{1-p}{p}$

The standard deviation of the geometric distribution is given by the following formula:

$\sigma = \sqrt{\frac{1-p}{p^{2}}$

In this problem, we have that:

$p = 0.383$

$\mu = \frac{1-p}{p} = \frac{1-0.383}{0.383} = 1.61$

$\sigma = \sqrt{\frac{1-p}{p^{2}}} = \sqrt{\frac{1-0.383}{(0.383)^{2}}} = 2.05$

(a) What is the probability that a drought lasts exactly 3 intervals?

This is $f(3)$

$f(x) = (1-p)^{x}p$

$f(3) = (1-0.383)^{3}*(0.383)$

$f(3) = 0.09$

There is a 9% probability that a drought lasts exactly 3 intervals.

At most 3 intervals?

This is $P = f(0) + f(1) + f(2) + f(3)$

$f(x) = (1-p)^{x}p$

$f(0) = (1-0.383)^{0}*(0.383) = 0.383$

$f(1) = (1-0.383)^{1}*(0.383) = 0.236$

$f(2) = (1-0.383)^{2}*(0.383) = 0.146$

Previously in this exercise, we found that $f(3) = 0.09$

$P = f(0) + f(1) + f(2) + f(3) = 0.383 + 0.236 + 0.146 + 0.09 = 0.855$

There is an 85.5% probability that a drought lasts at most 3 intervals.

(b) What is the probability that the length of a drought exceeds its mean value by at least one standard deviation?

This is $P(X \geq \mu+\sigma) = P(X \geq 1.61 + 2.05) = P(X \geq 3.66) = P(X \geq 4)$ .

We are working with discrete data, so 3.66 is rounded up to 4.

Either a drought lasts at least four months, or it lasts at most thee. In a), we found that the probability that it lasts at most 3 months is 0.855. The sum of these probabilities is decimal 1. So:

$P(X \leq 3) + P(X \geq 4) = 1$

$0.855 + P(X \geq 4) = 1$

$P(X \geq 4) = 0.145$

There is a 14.5% probability that the length of a drought exceeds its mean value by at least one standard deviation

8 0

3 years ago

What graph shows the system of linear equations for which (-3/2,0) is a solution

Tamiku [17]

Answer:

See description.

Step-by-step explanation:

Any graph where the two lines intersect at (-3/2, 0) will be the correct graph.

Here is an attached example.

8 0

3 years ago

AYUDAAAA, LES DOY CINCO ESTRELLAS SI LO RESUELVEN BIEN

liq [111]

dividido por la epotenusa es 7 :v

3 0

2 years ago

Felicity's dog eats no more than two cups of dog food per day. Felicity's dog eats at least one-quarter cup more than one-half o

horrorfan [7]

Answer:

$\frac{1}{4}+\frac{m}{2} \leq x\leq 2$

$x$ denotes amount of food that Felicity's dog eats

Step-by-step explanation:

Given:

Felicity's dog eats no more than two cups of dog food per day.

Felicity's dog eats at least one-quarter cup more than one-half of the amount Martin's dog eats.

The amount of food that Martin's dog eats is represented by using $m$

To find: the inequality that represents the situation

Solution:

Amount of food that Martin's dog eats = $m$

Amount of food that Felicity's dog eats ≤ 2

Also,

Amount of food that Felicity's dog eats $\geq \frac{1}{4}+\frac{m}{2}$

Therefore,

$\frac{1}{4}+\frac{m}{2}\leq$ Amount of food that Felicity's dog eats ≤ 2

Let $x$ denotes amount of food that Felicity's dog eats.

$\frac{1}{4}+\frac{m}{2}$ ≤ $\frac{1}{4}+\frac{m}{2} \leq x\leq 2$

3 0

3 years ago