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erastovalidia [21]
2 years ago
5

Write each phrase as an algebraic expression Two times n squared added to nine

Mathematics
2 answers:
Bad White [126]2 years ago
8 0
The answer for this question is 2n^2+9
expeople1 [14]2 years ago
7 0

Answer:

2n^2+9 is the phrase for correct expression

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On Monday Sophie ran 4 5/6 laps of a running track and on Tuesday she ran 5 3/4
MatroZZZ [7]

Answer:

10  7/12

hope this is right

Step-by-step explanation:

4  5/6 = 29/6 as an improper fraction

5  3/4 = 23/4 as an improper fraction

you times the two denominators together = 24

you times 29 by 4 = 116

you times 23 by 6 = 138

you add 116 and 138 = 254

you put this over 24 =  254/24

simplify this = 127/12

you make this a mixed number = 10 7/12

the answer is 10 7/12

3 0
3 years ago
If tan theta = startfraction 11 over 60 endfraction, what is the value of cot theta?
Dennis_Churaev [7]

The value of cot\theta when tan\theta =\frac{11}{60} comes to be \frac{60}{11}.

Given that trigonometric ratio:

tan\theta = \frac{11}{60}

<h3>What is the tangent of an angle?</h3>

The tangent of an angle is the ratio of the opposite side(to that angle) to the adjacent side(to that angle).

So, for the given problem

Opposite side to \theta = 11

Adjacent side to \theta = 60

So, cot \theta =\frac{AdjacentSide }{OppositeSide}

cot\theta =\frac{60}{11}

Therefore, the value of cot\theta when tan\theta =\frac{11}{60} comes to be \frac{60}{11}.

To get more about trigonometric ratios visit:

brainly.com/question/24349828

6 0
1 year ago
Pls if anyone knows the answer that will be greatly appreciated :)
shepuryov [24]

Answer:

For octagon =1080.......

Explanation:

180(8-2)

180×6

1080°

7 0
3 years ago
Look at the pic and help if you can thxxxx
givi [52]

Answer:

The 1,3,and 4.

Step-by-step explanation:

6 0
3 years ago
Write the slope-intercept equation of the line parallel to 5y = 2x + 20 that goes through (-1, 3).
poizon [28]

The first thing I'll do is solve "5y = 2x + 20" for "<span>y=</span>", so that I can find my reference slope:

y = (2/5)x + 4;

So the reference slope from the reference line is <span>m = 2/5;</span>.

Now I need to find two new slopes, and use them with the point they've given me; namely, with the point (-1, 3). They want me to find the line through (4, –1) that is parallel to 5y = 2x + 20; that is, through the given point, they want me to find a line that has the same slope as the reference line. 

Since a parallel line has an identical slope, then the parallel line through (-1, 3) will have slope <span>m = 2/5</span>. Now I have a point and a slope! So I'll use the point-slope form to find the line: y - 3 = (2/5)( x + 1);

Finally, y = (2/5)x + 17/5;


3 0
3 years ago
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