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3 years ago

Write each phrase as an algebraic expression Two times n squared added to nine

Mathematics

2 answers:

Bad White [126]3 years ago

8 0

The answer for this question is 2n^2+9

expeople1 [14]3 years ago

7 0

Answer:

2n^2+9 is the phrase for correct expression

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Find the area of this circle. Use 3.14 for . A circle has diameter 62 feet. 62 ft

EastWind [94]

Answer:

3017.54

Step-by-step explanation:

Volume for area of circle is A = Pie ( Or in this case 3.14 ) * radius ^ 2

Plug in the numbers 3.14 * 31 ^2

31 is half the diameter or the radius

Answer = 3017.54

4 0

3 years ago

Glenda earned $34.72 for 2.8 hours of work. What was her hourly wage?

Bond [772]

Answer: $12.4

Step-by-step explanation:

34.72/2.8 hours = 12.4 dollars/hr

4 0

2 years ago

Write an equation to show the relationship between a and c when a = b + 9 b = c - 2

ICE Princess25 [194]

Given:

The equations are:

$a=b+9$

$b=c-2$

To find:

The equation that show the relationship between a and c.

Solution:

We have,

$a=b+9$ ...(i)

$b=c-2$ ...(ii)

Equation (i) can be rewritten as:

$a-9=b$ ...(iii)

From (ii) and (iii), we get

$a-9=c-2$

$a-c=9-2$

$a-c=7$

Therefore, the required equation is $a-c=7$ .

4 0

3 years ago

a student ran out of time on a multiple choice exam and randomly guess the answers for two problems each problem have four answe

katen-ka-za [31]

Answer:

The probability that he answered neither of the problems correctly is 0.0625.

Step-by-step explanation:

We are given that a student ran out of time on a multiple-choice exam and randomly guess the answers for two problems each problem have four answer choices ABCD and only one correct answer.

Let X = Number of problems correctly answered by a student.

The above situation can be represented through binomial distribution;

$P(X=r)=\binom{n}{r}\times p^{r}\times (1-p)^{n-r};x=0,1,2,3,....$

where, n = number of trials (samples) taken = 2 problems

r = number of success = neither of the problems are correct

p = probability of success which in our question is probability that

a student answer correctly, i.e; p = $\frac{1}{4}$ = 0.75.

So, X ~ Binom(n = 2, p = 0.75)

Now, the probability that he answered neither of the problems correctly is given by = P(X = 0)

P(X = 0) = $\binom{2}{0}\times 0.75^{0}\times (1-0.75)^{2-0}$

= $1 \times 1\times 0.25^{2}$

= 0.0625

6 0

4 years ago

Ill give brainliest and 5 stars and thanks if answer this what is the result of substituting for y in the bottom equation

GREYUIT [131]

We have two set of solutions , ( $\frac{\sqrt{29} }{2}$ , $\frac{\sqrt{29} }{2}$ + 3 ) , ( - $\frac{\sqrt{29} }{2}$ + 3 , - $\frac{\sqrt{29} }{2}$ + 3).

Step-by-step explanation:

We have , the following equations:

$y = x+3$ and $y = x^{2} +2x -4$ . Let's substitute value of y in bottom equation:

⇒ $y = x^{2} +2x -4$

⇒ $x+3 = x^{2} +2x -4$

⇒ $x^{2} +x -7= 0$

Roots of quadratic equation are given by: a = 1, b= 1 , c = -7

$x = \frac{\sqrt{b^{2}-4ac} }{2a}$

⇒ $x = \frac{\sqrt{b^{2}-4ac} }{2a}$

⇒ $x = \frac{\sqrt{1^{2}-4(1)(-7)} }{2(1)}$

⇒ $x = \frac{\sqrt{29} }{2}$ which is actually x = ± $\frac{\sqrt{29} }{2}$ .

We know that $y = x+3$ ,

⇒ y = ± $\frac{\sqrt{29} }{2}$ + 3.

We have two set of solutions , ( $\frac{\sqrt{29} }{2}$ , $\frac{\sqrt{29} }{2}$ + 3 ) , ( - $\frac{\sqrt{29} }{2}$ + 3 , - $\frac{\sqrt{29} }{2}$ + 3).

5 0

3 years ago