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2 years ago

Write each phrase as an algebraic expression Two times n squared added to nine

Mathematics

2 answers:

Bad White [126]2 years ago

8 0

The answer for this question is 2n^2+9

expeople1 [14]2 years ago

7 0

Answer:

2n^2+9 is the phrase for correct expression

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What are the center and radius of the circle defined by the equation x2 + y2 - 6x+By+21=0 ?

podryga [215]

(x-3)2+(y+B2)2+By=-12+B24

5 0

3 years ago

What is 13 10/15 in the lowest terms?

olga55 [171]

The answer is below:

$13\frac{2}{3}$

5 0

3 years ago

Find a 75% confidence interval for the population average weight μ of all adult mountain lions in the specified region. (Round y

kupik [55]

Answer:

75% confidence interval is 91.8±16.66. That is between 75.1 and 108.5 pounds.

Step-by-step explanation:

The question is missing. It is as follows:

Adult wild mountain lions (18 months or older) captured and released for the first time in the San Andres Mountains had the following weights (pounds): 69 104 125 129 60 64

Assume that the population of x values has an approximately normal distribution.

Find a 75% confidence interval for the population average weight μ of all adult mountain lions in the specified region. (Round your answers to one decimal place.)

75% Confidence Interval can be calculated using M±ME where

M is the sample mean weight of the wild mountain lions ( $\frac{69 +104 +125 +129+60 +64}{6} =91.8$ )

ME is the margin of error of the mean

And margin of error (ME) of the mean can be calculated using the formula

ME= $\frac{t*s}{\sqrt{N} }$ where

t is the corresponding statistic in the 75% confidence level and 5 degrees of freedom (1.30)

s is the standard deviation of the sample(31.4)

N is the sample size (6)

Thus, ME= $\frac{1.30*31.4}{\sqrt{6} }$ ≈16.66

Then 75% confidence interval is 91.8±16.66. That is between 75.1 and 108.5

3 0

3 years ago

Use the laws of Sines and law of cosines to find missing dimensions

Andrei [34K]

Answer:

A) ERROR

B) ∠C = 26°

Step-by-step explanation:

Houston, We have a problem!!! too much information

If we had a legit triangle, the law of sines would hold

19/sin138 = 8/sin20

28.395 = 23.390

as this is NOT an equality, the triangle does not exist as described.

IF it did, we'd get different results depending on which set we used

∠F = 180 - 138 - 20 = 22°

Law of sines

19/sin138 = DE/sin22 ⇒ DE = 19sin22/sin138 = 10.63697...

8/sin20 = DE/sin22 ⇒ DE = 8sin22/sin20 = 8.762211...

If we attempt to use Law of cosines

DE² = 19² + 8² - 2(19)(8)cos22 = 11.9639...

so really none is correct because we attempt to use trig calculations to a non-triangle.

12) AC² = 15² + 19² - 2(15)(19)cos120

AC = 29.51270...

29.51270 / sin120 = 15/sinC

C = arcsin(15sin120/29.51270) = 26.1142... 26°

6 0

2 years ago

Read 2 more answers

Hey can someone help me and check my answers? thanks <3

Tasya [4]

Remember
x^-m=1/(x^m)
u^-3=1/(u^3)
1/(u^3)=1/125
therefor
u^3=125
u=5

x=-3
easy
y=-3-13
y=-16
correct

normally, y is output
(x,y)
chose al second numbers
0,3 are all acceptable
B and D

y=mx+b
m=-3
y=-3x+b
sub point
(x,y)
(1,-2)
-2=-3(1)+b
-2=-3+b
1=b
y=-3x+1

remember (x,y) you keep swtiching those

3 0

3 years ago