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andreyandreev [35.5K]
3 years ago
13

mary is delivering a load of goods to vancover bc to seattle wa and then in seattle she is picking up another load to deliver to

albuquerque nm. The distance for vancouver to seattle is 220 km and the distance from seattle to albuquerque is 1456 mi. The odometer in marys truck records distance in kilometers
Mathematics
1 answer:
JulijaS [17]3 years ago
4 0

Answer:

2,550 km,154767- when mary left vancouver,157317 in Albuquerque

Step-by-step explanation:

1 mile=1.6 km

1456 miles= 1.6*1456=2330 km

2330 km+ 220 km= 2550 km from vanc to alber

154987-220=154767 km when mary left vancouver

154987+2330=157317 in Albuquerque

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vlada-n [284]
D maybe................
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3 years ago
Read 2 more answers
Write the decimal for the expanded form given below.<br><br> 60+7 + 0.3 + 0.05+0.003
svet-max [94.6K]

Answer: 67.353

Step-by-step explanation:

 60.000

+07.000

+00.300           Writing the numbers like this helps me keep track of them!

+00.050        It lets me see what place each number is in relative to the others

+00.003

67.353

5 0
3 years ago
Find the limit, if it exists, or type dne if it does not exist.
Phantasy [73]
\displaystyle\lim_{(x,y)\to(0,0)}\frac{\left(x+23y)^2}{x^2+529y^2}

Suppose we choose a path along the x-axis, so that y=0:

\displaystyle\lim_{x\to0}\frac{x^2}{x^2}=\lim_{x\to0}1=1

On the other hand, let's consider an arbitrary line through the origin, y=kx:

\displaystyle\lim_{x\to0}\frac{(x+23kx)^2}{x^2+529(kx)^2}=\lim_{x\to0}\frac{(23k+1)^2x^2}{(529k^2+1)x^2}=\lim_{x\to0}\frac{(23k+1)^2}{529k^2+1}=\dfrac{(23k+1)^2}{529k^2+1}

The value of the limit then depends on k, which means the limit is not the same across all possible paths toward the origin, and so the limit does not exist.
8 0
4 years ago
What is the product?
ZanzabumX [31]

Answer:

The product is:

\left[\begin{array}{cc}15 & 14\\-1 & 9\end{array}\right]

Step-by-step explanation:

For this problem you need to multiply the first row only for the two first column of the others matrix and get the desired result:

\left[\begin{array}{ccc}1&3&1\\-2&1&0\end{array}\right] \times \left[\begin{array}{cc}2&-2\\3&5\\4&1\end{array}\right]

1 \times 2 + 3 \times 3 + 1 \times -2 = 15

So the value of the element in the position a_{11} is 15

1 \times -2 + 3 \times 5 + 1 \times 1 = 14

So the value of the element in the position a_{12} is 14

Then with these two values you can determinate the result matrix.

\left[\begin{array}{cc}15 & 14\\-1 & 9\end{array}\right]

3 0
2 years ago
A school band is buying new jackets and hats. A jacket costs $100 and a hat costs $40. The expression 100/+40h represents the co
erastova [34]

Answer:

820

Step-by-step explanation:

100j+40h

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820!

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