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3 years ago

Ray created the list of factors for 48 below.

Mathematics

2 answers:

brilliants [131]3 years ago

3 0

Answer:

Step-by-step explanation:

also why is 78 there? a factor means in that range

horsena [70]3 years ago

3 0

Answer:7

Seven should be removed from his list

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Find the sum of the first 21 terms of the arithmetic sequence 5, -2, -9.

USPshnik [31]

The correct answer is idk for me

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3 years ago

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Find the slope given the following ordered <br><br> 2,-3 and 6,-13

saw5 [17]

You would have to use this equation : y2-y1/x2-x1 = slope

So it would be -13 +3/6-2= -10/4

Simplify it and you get : -5/2

Slope is -5/2

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2 years ago

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in a classroom of 1/6 of the students were wearing blue and 2/3 are wearing white there are thirty six students in the class how

jeyben [28]

Answer:

Step-by-step explanation:

1/6 of 36=6

2/3 of 36= 24

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2 years ago

I need help and if you can explain how to do all of the work that would be great

drek231 [11]

A because cmon its tuesday

lol no thats not the reason but im very too very sure that this is the answer

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3 years ago

Use the rules of exponents to simplify the expressions. Match the expression with its equivalent value.

Lelechka [254]

Answer:

1) $\frac{(-2)^{-5}}{(-2)^{-10}}=-32$

2) $2^{-1}.2^{-4} = \frac{1}{32}$

3) $(-\frac{1}{2} )^3.(-\frac{1}{2} )^2=-\frac{1}{32}$

4) $\frac{2}{2^{-4}} = 32$

Step-by-step explanation:

1) $\frac{(-2)^{-5}}{(-2)^{-10}}$

Solving using exponent rule: $a^{-m}=\frac{1}{a^m}$

$\frac{(-2)^{-5}}{(-2)^{-10}}\\=(-2)^{-5+10}\\=(-2)^{5}\\=-32$

So, $\frac{(-2)^{-5}}{(-2)^{-10}}=-32$

2) $2^{-1}.2^{-4}$

Using the exponent rule: $a^m.a^n=a^{m+n}$

We have:

$2^{-1}.2^{-4}\\=2^{-1-4}\\=2^{-5}$

We also know that: $a^{-m}=\frac{1}{a^m}$

Using this rule:

$2^{-5}\\=\frac{1}{2^5}\\=\frac{1}{32}$

So, $2^{-1}.2^{-4} = \frac{1}{32}$

3) $(-\frac{1}{2} )^3.(-\frac{1}{2} )^2$

Solving:

$(-\frac{1}{2} )^3.(-\frac{1}{2} )^2\\=(-\frac{1}{8} ).(\frac{1}{4} )\\=-\frac{1}{32}$

So, $(-\frac{1}{2} )^3.(-\frac{1}{2} )^2=-\frac{1}{32}$

4) $\frac{2}{2^{-4}}$

We know that: $a^{-m}=\frac{1}{a^m}$

$\frac{2}{2^{-4}}\\=2\times 2^4\\=2(16)\\=32$

So, $\frac{2}{2^{-4}} = 32$

3 0

3 years ago