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Over [174]
3 years ago
7

Ray created the list of factors for 48 below.

Mathematics
2 answers:
brilliants [131]3 years ago
3 0

Answer:

7

Step-by-step explanation:

also why is 78 there? a factor means in that range

horsena [70]3 years ago
3 0
Answer:7

Seven should be removed from his list
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Find the sum of the first 21 terms of the arithmetic sequence 5, -2, -9.
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Find the slope given the following ordered <br><br> 2,-3 and 6,-13
saw5 [17]

You would have to use this equation : y2-y1/x2-x1 = slope

So it would be -13 +3/6-2= -10/4

Simplify it and you get : -5/2

Slope is -5/2

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in a classroom of 1/6 of the students were wearing blue and 2/3 are wearing white there are thirty six students in the class how
jeyben [28]

Answer:

6

Step-by-step explanation:

1/6 of 36=6

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2 years ago
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A because cmon its tuesday

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6 0
3 years ago
Use the rules of exponents to simplify the expressions. Match the expression with its equivalent value.
Lelechka [254]

Answer:

1) \frac{(-2)^{-5}}{(-2)^{-10}}=-32

2) 2^{-1}.2^{-4} = \frac{1}{32}

3) (-\frac{1}{2} )^3.(-\frac{1}{2} )^2=-\frac{1}{32}

4) \frac{2}{2^{-4}} = 32

Step-by-step explanation:

1) \frac{(-2)^{-5}}{(-2)^{-10}}

Solving using exponent rule: a^{-m}=\frac{1}{a^m}

\frac{(-2)^{-5}}{(-2)^{-10}}\\=(-2)^{-5+10}\\=(-2)^{5}\\=-32

So, \frac{(-2)^{-5}}{(-2)^{-10}}=-32

2) 2^{-1}.2^{-4}

Using the exponent rule: a^m.a^n=a^{m+n}

We have:

2^{-1}.2^{-4}\\=2^{-1-4}\\=2^{-5}

We also know that: a^{-m}=\frac{1}{a^m}

Using this rule:

2^{-5}\\=\frac{1}{2^5}\\=\frac{1}{32}

So, 2^{-1}.2^{-4} = \frac{1}{32}

3) (-\frac{1}{2} )^3.(-\frac{1}{2} )^2

Solving:

(-\frac{1}{2} )^3.(-\frac{1}{2} )^2\\=(-\frac{1}{8} ).(\frac{1}{4} )\\=-\frac{1}{32}

So, (-\frac{1}{2} )^3.(-\frac{1}{2} )^2=-\frac{1}{32}

4) \frac{2}{2^{-4}}

We know that: a^{-m}=\frac{1}{a^m}

\frac{2}{2^{-4}}\\=2\times 2^4\\=2(16)\\=32

So, \frac{2}{2^{-4}} = 32

3 0
3 years ago
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