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Radda [10]
3 years ago
9

How many moles of mgci2 are there in 318 g of the compound?

Mathematics
1 answer:
shusha [124]3 years ago
7 0

Answer:

there are 3.3399 moles in 318 grams! ✔️

Step-by-step explanation:

So we know that 100 grams MgCl2 to mol = 1.0503 mol.

Therefore, to find the number of moles in 318g of the compound, we use the rule of three:

if 1.0503 mol -------------> 100 grams

       X            <------------- 318 grams

The solution is: X = (318*1.0503)/100 = 3.3399 mol.

Summarizing, there are 3.3399 moles in 318 grams! ✔️

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\frac{2}{x}

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<h2>Step-by-step explanation:</h2>

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To solve this using only positive exponents, follow these steps:

i. Rewrite the expression in a clearer form

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ii. The position of the term with negative exponent is changed from denominator to numerator or numerator to denominator depending on its initial position. If it is at the numerator, it is moved to the denominator. If otherwise it is at the denominator, it is moved to the numerator. When this is done, the negative exponent is changed to positive.

In our case, the first term has a negative exponent and it is at the numerator. We therefore move it to the denominator and change the negative exponent to  positive as follows;

\frac{1}{2x^3} . 4x^2

iii. We then solve the result as follows;

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b. 2x^4 • 4x^-3

i. Rewrite as follows;

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ii. The second term has a negative exponent, therefore swap its position and change the negative exponent to a positive one.

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\frac{x}{2}

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c. 2x^3y^-3 • 2x

i. Rewrite as follows;

2x³y⁻³ . 2x

ii. Change position of terms with negative exponents;

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iii. Now solve;

\frac{4x^4}{y^3}

Therefore, 2x³y⁻³ . 2x = \frac{4x^4}{y^3}

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