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3 years ago

15

I'm not sure to use 6 or 10 for a side length

1 answer:

dlinn [17]3 years ago

6 0

Answer:

10

Step-by-step explanation:

6 is the width not the length

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What is the answer for this

Georgia [21]

The domain is all real numbers

5 0

3 years ago

What is coordinate geometry

Elina [12.6K]

is the study of algebraic equations on graphs

An example of the coordinate geometry is plotting point,lines and curves on

an x & Y axis thanks

7 0

3 years ago

Given: <br><br> ∆SPM, PK⊥ SM<br><br> SP = 25, SM = 28, PK = 9<br><br> Find: m∠S, m∠M, PM

nevsk [136]

Answer:

∠S = 21.10°

∠M = 79.45°

PM = 9.16

Step-by-step explanation:

Here Pythagorean theorem and trigonometry suffice to solve our problem.

From the Pythagorean theorem we get:

$KM^2+9^2=PM^2$ and

$(25-KM)^2+9^2=25^2.$

We solve for $KM$ in the second equation and get:

$(25-KM)=\sqrt{25^2-9^2}$

$\therefore KM=25-\sqrt{25^2-9^2} =\boxed{1.68}$

Now since

$SK+KM=25\\\\ SK=\boxed{23.32}$

Therefore

${\angle}S=Tan^{-1}(\frac{PK}{SK}) = Tan^{-1}(\frac{9}{23.32})=21.10^o$

and

${\angle}M=Tan^{-1}(\frac{PK}{KM}) = Tan^{-1}(\frac{9}{1.68})=79.45^o.$

And finally again from the Pythagorean theorem:

$PM^2=PK^2+KM^2=9^2+1.68^2$

$\therefore PM=\sqrt{9^2+1.68^2} =9.16.$

Thus,

∠S = 21.10°

∠M = 79.45°

PM = 9.16.

7 0

3 years ago

Solve the system of equations of equations by graphing on your calculator rounded to 3 decimal spaces

Vanyuwa [196]

Answer:

$x=2.333\\y=-1,667$

Step-by-step explanation:

we have

$y-x=-4$ ----> equation A

$2x+y=3$ ----> equation B

Solve the system of equations by graphing

Remember that the solution of the system is the intersection point both graphs

Using a graphing tool

The intersection point is (2.333,-1.667)

see the attached figure

therefore

The solution is

$x=2.333\\y=-1,667$

3 0

3 years ago

Trigonometry that’s due in one hour :(

expeople1 [14]

Answer:

(a) $\theta=\tan^{-1}(-0.890)$

$\implies \theta=-41.66908262 \pm 180 \textdegree n$

$\implies \theta=138.3309174..., 318.3309174...$

$\implies \theta=138\textdegree, 318\textdegree$

(b) $\theta=\cos^{-1}\left(\dfrac{\sqrt{3} }{2}\right)$

$\implies \theta=30 \textdegree \pm360 \textdegree n, 330 \textdegree \pm360 \textdegree n$

$\implies \theta=30 \textdegree , 330 \textdegree$

(c) $\theta=\sin^{-1}\left(\dfrac{1 }{2}\right)$

$\implies \theta=30 \textdegree \pm360 \textdegree n, 150 \textdegree \pm360 \textdegree n$

$\implies \theta=30 \textdegree , 150 \textdegree$

3 0

2 years ago