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natta225 [31]
3 years ago
13

Jill flipped a coin 40 times. The coin landed as heads 28 times and tails 12 times. Based on her results, which of the following

is true?
Mathematics
2 answers:
ella [17]3 years ago
8 0
There are many conclusions we can come to for this!

70% of the flips were heads, and 30% are tails

28/40 was heads, and 12/40 were tails

There were more heads than tails

There were 14 more heads than tails

:)
zaharov [31]3 years ago
3 0
I don't see any "following", but whatever is the question both results are true
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Stacia bought an unlocked iPhone for $289. The tax was 8.5%. What was the total cost of the phone? How did you arrive at your an
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The answer is 313.56 because 289 + (8.5%=24.65)=313.56
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3 years ago
What is the slope of the line that passes through the points (-4,-2) and (-4,-22)? Write your answer in simplest form.​
Anuta_ua [19.1K]

Answer:

20x  - 4 = 0

Step-by-step explanation:

\frac{y - y1 }{y2 - y1}  =  \frac{x - x1}{x2 - x1}  \\ x1 =  - 4 \\ y1 =  - 2 \\ x2 =  - 4 \\ y2 =  - 22

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8 0
3 years ago
There are 4 green marbles and 2 red marbles in the jar. You just randomly draw one by one without replacement and stop when you
zalisa [80]

Answer:

Then the probability distribution is:

P(0) = 1/3

P(1) = 4/15

P(2) = 1/5

P(3)  = 2/15

P(4) = 1/15

The expected value for X is:

EV = 1.33...

Step-by-step explanation:

We have a total of 6 marbles in the jar.

The probability of getting a red marble in the first try  (X = 0) is equal to the quotient between the number of red marbles and the total number of marbles, this is:

P(0) = 2/6 = 1/3

The probability of drawing one green marble (X = 1)

is:

First, you draw a green marble with a probability of 4/6

Then you draw the red one, but now there are 5 marbles in the jar (2 red ones and 3 green ones), then the probability is 2/5

The joint probability is:

P(1) = (4/6)*(2/5) = (2/3)*(2/5) = 4/15

The probability of drawing two green marbles (X  = 2)

Again, first we draw a green marble with a probability of 4/6

Now we draw again a green marble, now there are 3 green marbles and 5 total marbles in the jar, so this time the probability is 3/5

Now we draw the red marble (there are 2 red marbles and 4 total marbles in the jar), with a probability of 2/4

The joint probability is:

P(2) = (4/6)*(3/5)*(2/4) = (2/6)*(3/5) = 1/5

The probability of drawing 3 green marbles (X = 3)

At this point you may already understand the pattern:

First, we draw a green marble with a probability 4/6

second, we draw a green marble with a probability 3/5

third, we draw a green marble with a probability 2/4

finally, we draw a red marble with a probability 2/3

The joint probability is:

P(3) = (4/6)*(3/5)*(2/4)*(2/3) = (2/6)*(3/5)*(2/3) = (1/5)*(2/3) = (2/15)

Finally, the probability of drawing four green marbles (X = 4) is given by:

First, we draw a green marble with a probability 4/6

second, we draw a green marble with a probability 3/5

third, we draw a green marble with a probability 2/4

fourth, we draw a green marble with a probability 1/3

Finally, we draw a red marble with a probability 2/2 = 1

The joint probability is:

P(4) = (4/6)*(3/5)*(2/4)*(1/3)*1 = (1/5)*(1/3) = 1/15

Then the probability distribution is:

P(0) = 1/3

P(1) = 4/15

P(2) = 1/5

P(3)  = 2/15

P(4) = 1/15

The expected value will be:

EV = 0*P(0) + 1*P(1) + 2*P(2) + 3*P(3) + 4*P(4)

EV = 1*(4/15) + 2*( 1/5) + 3*( 2/15) + 4*(1/15 ) = 1.33

So we can expect to draw 1.33 green marbles in this experiment.

5 0
3 years ago
...............................................
slavikrds [6]
What exactly are you asking?
5 0
3 years ago
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