Hmm, one way we can do this is by assigning numbers to each
A=4 and B=3
A>B because 4>3
so
A. 2(A+B)=2(4+3)=2(7)=14
B. A+B^2=4+3^2=4+9=13
C. A^2+B^2=4^2+3^2=16+9=25
D. A^2-B^2=4^2-3^2=16-9=7
the largest is 25 so C
Answer:
x=16
Step-by-step explanation:
Because of Thales Intercept Theorem, AN/NG=NE/GL
NE/GL=1/2, AG=2x-9+x+7=3x-2
2x-9/3x-2=1/2
x=16
Hello from MrBillDoesMath!
Answer:
No. That problem cited is one of 3 great unsolved problems of antiquity. See https://en.wikipedia.org/wiki/Angle_trisection for details.
Regards,
MrB
P.S. I'll be on vacation from Friday, Dec 22 to Jan 2, 2019. Have a Great New Year!
