4 years ago

Which of the following ratios is equivalent to 1/cos?

Mathematics

1 answer:

Andrew [12]4 years ago

8 0

Secant

Remember it by linking the third letter:
SeCant = 1/Cos
CoSecant = 1/Sin
CoTangent = 1/Tan

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Students were packed shoulder to shoulder in a gym for a pep rally. The students were in a rectangular shaped area of 7,500 ft2.

hram777 [196]

Answer: 1527

Step-by-step explanation:

Total Area = 7500 ft^2

Area covered by one student = Area of one circle

= π*r^2

r = radius of circle = 2.5/2 = 1.25 ft

Area covered by one student = π*1.25^2 = 4.91 ft^2

Number of students who can fit into total area = Total Area/Area covered by one student

Number of students who can fit into total area = 7500/4.91 = 1527.49

Hence the answer is 1527 students

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I believe it's $2250 since you just subtract.

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3 years ago

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What two numbers add to be 6 and multiply to be 15

yarga [219]

$\displaystyle \bf \\
x_1+x_2=6\\\\
x_1\cdot x_2=15\\\\
\Longrightarrow~~x^2-6x+15=0\\\\
x_{12}=\frac{-b\pm\sqrt{b^2-4ac}}{2a}=\frac{6\pm\sqrt{36-60}}{2}=\\\\
=\frac{6\pm\sqrt{-24}}{2}=\frac{6\pm2\sqrt{-6} }{2}=3\pm i\sqrt{6}\\\\
x_1=\boxed{3-i\sqrt{6}}\\\\
x_2=\boxed{3+i\sqrt{6}}\\\\
\texttt{Verify:}\\\\
x_1+x_2=3-\underline{i\sqrt{6}}+3+\underline{i\sqrt{6}}=3+3=6~~correct\\\\
x_1\cdot x_2=(3-i\sqrt{6})(3+i\sqrt{6})=3^2-(i\sqrt{6})^2=9+6=15~~correct$

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