3 years ago

If I have a 93% as my subject grade and I get an 68% percent on a quiz as a quiz grade, what is my final subject grade.

Mathematics

1 answer:

trapecia [35]3 years ago

4 0

Answer:

Password for the 1hdhhdhfhdhrhehjfujdjwjwjdjhf

Step-by-step explanation:

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irina1246 [14]

J should be the correct answer

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2 years ago

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4. solve e) 4^x-10.2^x+16=0 I think the dot means multiply?

suter [353]

$4^x-10\cdot2^x+16=0\Rightarrow(2^2)^x-10\cdot2^x+16=0\Rightarrow(2^x)^2-10\cdot2^x+16=0$

$subtitute\ 2^x=t > 0\\\\t^2-10t+16=0\\t^2-2t-8t+16=0\\t(t-2)-8(t-2)=0\\(t-2)(t-8)=0\iff t-2=0\ or\ t-8=0\\\\t=2\ or\ t=8\\\\t=2^1\ or\ t=2^3\\\\therefore\ 2^x=2^1\ or\ 2^x=2^3\\\\Answer:\boxed{x=1\ or\ x=3}$

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3 years ago

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PLEASE ANSWER + BRAINLIEST!! Factor completely. 4k - 20k^9 = 3b^2 - 108 =

Neporo4naja [7]

$4k-20k^9=4k(1-5k^8)=4k\left[1^2-(k^4\sqrt5)^2\right]\\\\=4k(1-k^4\sqrt5)(1+k^4\sqrt5)=4k\left[1^2-(k^2\sqrt[4]5)^2\right](1+k^4\sqrt5)\\\\=4k(1-k^2\sqrt[4]5)(1+k^2\sqrt[4]5)(1+k^4\sqrt5)\\\\=4k\left[1^2-(k\sqrt[8]5)^2\right](1+k^2\sqrt[4]5)(1+k^4\sqrt5)\\\\=4k(1-k\sqrt[8]5)(1+k\sqrt[8]5)(1+k^2\sqrt[4]5)(1+k^4\sqrt5)$

$3b^2-108=3(b^2-36)=3(b^2-6^2)=3(b-6)(b+6)$

$Used:\ (a-b)(a+b)=a^2-b^2$

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3 years ago

2 The area of the back yard is 72m. The length is 12m. What is

meriva

2. 6m
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2 years ago

Write the equation of a line PERPENDICULAR to the line y = 3x + 2 that passes through

Dominik [7]

Answer:

Step-by-step explanation:

how 7 because the digris that know be a last number and can be sure the meaning are complecataed thats tight

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2 years ago