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svp [43]
3 years ago
8

The sum of two consecutive integers is 41. What are the integers?

Mathematics
1 answer:
Zolol [24]3 years ago
4 0
Let the consecutive integers be x and x+1

x+x+1 = 41
2x+1 = 41
2x= 41-1 = 40
x = 40/2 = 20

The integers are 20 and 21
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What fraction is greater than 1/2 but less than 3/4
aliya0001 [1]
1/2 = 50%

3/4 = 75%

So something in between that could be 2/3 (which equals 66.67% )

A few others could be: 3/5 ( equals to 60% ) , 7/10 ( equals 70%) 

Hope that helps :)

5 0
3 years ago
Read 2 more answers
(X^3+1)dividend (x-1)
bazaltina [42]

x^3=x\cdot x^2 and x^2(x-1)=x^3-x^2. So we have a remainder of

(x^3+1)-(x^3-x^2)=x^2+1

x^2=x\cdot x and x(x-1)=x^2-x. Subtracting this from the previous remainder gives a new remainder

(x^2+1)-(x^2-x)=x+1

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and we're done since 2 does not divide x. So we have

\dfrac{x^3+1}{x-1}=x^2+x+1+\dfrac2{x-1}

4 0
3 years ago
Which equation can be used to calculate the area of the shaded triangle in the figure below?
lozanna [386]

Answer:

A

Step-by-step explanation:

The area (A) of a triangle is calculated using the formula

A = \frac{1}{2} bh ( b is the base and h the perpendicular height )

here b = 14 and h = 4, hence

A = \frac{1}{2} (14 × 4) = 28

7 0
3 years ago
Câu 1: cho hình chóp S.ABC có đáy là tam giác đều cạnh bằng a, cạnh bên SB vuông góc với mặt phẳng (ABC) , SB =2a. Tính thể tích
Maurinko [17]

Answer:

\frac{\sqrt{3}}{6} a^{3} và \frac{a^{3} }{6}

Step-by-step explanation:

Câu 1: V = 1/3.2a.\frac{\sqrt{3}}{4}a^{2} = \frac{\sqrt{3}}{6} a^{3}

câu 2: Theo đề bài ta có SA là chiều cao và tam giác đáy SBC vuông tại S (hình chóp S.ABC đổi thành chóp A.SBC)

=> V = 1/3 SA.(diện tích tam giác SBC) = 1/3a.\frac{a^{2} }{2} = \frac{a^{3} }{6}

8 0
3 years ago
0645 + 0745 answer in military time
const2013 [10]

Answer:

1390

Step-by-step explanation:

6 0
3 years ago
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