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3 years ago

If you apply force on an object such as a ball, what will possibly happen to it?

Physics

1 answer:

alexandr402 [8]3 years ago

4 0

It will move in the direction you pushed it, but it will go at a certain velocity

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Un observador se halla a 510m. de una pared. entre el observador y la pared, y a igual distancia de ambos, se realiza un disparo

ch4aika [34]

Answer:

a) t = 0.75 s, b) t = 2.25 s

Explanation:

The speed of sound is constant in a material medium

v = 340 m / s

we can use the relations of uniform motion to find the time

v = x / t

t = x / v

In the exercise, the observer's distance to the wall is indicated d = 510 m, it also indicates that the shot is fired at the midpoint

x = d / 2

a) direct sound the distance from the observer to the screen is

x = 510/2 = 255 m

t = 255/340

t = 0.75 s

b) echo sound.

In this case the sound reaches the wall bounces, the distance is

x = d / 2 + d

x = 3/2 d

x = 3/2 510

x = 765 m

the time is

t = x / v

t = 765/340

t = 2.25 s

5 0

3 years ago

PLS HELP How much power is used if an athlete lives a 100n Weight up 5m in 20 seconds

BlackZzzverrR [31]

Answer:

25J

Explanation:

power = work done ÷ time taken.

and work done = force applied × distance covered.

according to the question, the athlete lifts the weight of 100N upto 5m therefore;

100N × 5m = 500N/m

then onwards,

the work done (500 N/m) should be divided by the time taken to calculate the power,

500 ÷ 20s = 25J

is your answer.

hope this helped. :)

8 0

3 years ago

Read 2 more answers

A sled drops 50 meters in height on a hill. The mass of the rider and sled is 70 kg and the sled is going 10 m/s at the bottom o

navik [9.2K]

Answer:

Efficiency = 10.2 %

Explanation:

Given the following data;

Mass = 70 kg

Height = 50 m

Velocity = 10 m/s

We know that acceleration due to gravity is equal to 9.8 m/s².

To find the efficiency of energy conversion from potential to kinetic;

First of all, we would determine the potential energy;

P.E = mgh

P.E = 70 * 9.8 * 50

P.E = 34300 J

For the kinetic energy;

K.E = ½mv²

K.E = ½ * 70 * 10²

K.E = 35 * 100

K.E = 3500

Therefore, Input energy, I = 34300 J

Output energy, O = 3500 J

Next, we find the efficiency;

Efficiency = O/I * 100

Substituting into the formula, we have;

Efficiency = 3500/34300 * 100

Efficiency = 0.1020 * 100

Efficiency = 10.2 %

4 0

3 years ago

A 0.3-m-radius automobile tire rotates how many revolutions after starting from rest and accelerating at a constant 2.13 rad/s2

Aloiza [94]

Answer:

The automobile tire rotates 91 revolutions

Explanation:

Given;

angular acceleration of the automobile, α = 2.13 rad/s²

time interval, t = 23.2-s

To calculate the number of revolutions, we apply the first kinematic equation;

$\theta = \omega_i \ + \frac{1}{2} \alpha t^2$

the initial angular velocity is zero,

$\theta =0\ + \frac{1}{2} (2.13) (23.2)^2\\\\\theta = 573.2256 \ Rad$

Find how many revolutions that are in 573.2256 Rad

$N = \frac{\theta}{2 \pi} = \frac{573.2256}{2\pi} \\\\N = 91 \ revolutions$

Therefore, the automobile tire rotates 91 revolutions

3 0

4 years ago

A radio have a wavelength of 0.3m and travels at a speed of 300,000,000 m/s. What is the frequency of this wave?

Ilya [14]

The frequency of the wave is $1\cdot 10^9 Hz$

Explanation:

The frequency, the wavelength and the speed of a wave are related by the following equation:

$c=f \lambda$

where

c is the speed of the wave

f is the frequency

$\lambda$ is the wavelength

For the radio wave in this problem,

$\lambda = 0.3 m$

$c=300,000,000 m/s = 3\cdot 10^8 m/s$

Therefore, the frequency is:

$f=\frac{c}{\lambda}=\frac{3\cdot 10^8}{0.3}=1\cdot 10^9 Hz$

Learn more about waves here:

brainly.com/question/5354733

brainly.com/question/9077368

#LearnwithBrainly

4 0

3 years ago

If you apply force on an object such as a ball, what will possibly happen to it?​

If you apply force on an object such as a ball, what will possibly happen to it?