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iren [92.7K]
2 years ago
6

A radio have a wavelength of 0.3m and travels at a speed of 300,000,000 m/s. What is the frequency of this wave?​

Physics
1 answer:
Ilya [14]2 years ago
4 0

The frequency of the wave is 1\cdot 10^9 Hz

Explanation:

The frequency, the wavelength and the speed of a wave are related by the following equation:

c=f \lambda

where

c is the speed of the wave

f is the frequency

\lambda is the wavelength

For the radio wave in this problem,

\lambda = 0.3 m

c=300,000,000 m/s = 3\cdot 10^8 m/s

Therefore, the frequency is:

f=\frac{c}{\lambda}=\frac{3\cdot 10^8}{0.3}=1\cdot 10^9 Hz

Learn more about waves here:

brainly.com/question/5354733

brainly.com/question/9077368

#LearnwithBrainly

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The root quadratic equation of 2x^{2}  - 4x - 9 = 0 is x=\frac{2+\sqrt{22}}{2},\:x=\frac{2-\sqrt{22}}{2}

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To solve the quadratic equation use the formula of x=\frac{-b\pm \sqrt{b^2-4ac}}{2a}

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On comparing with 2x^{2}  - 4x - 9 = 0

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X==\frac{-\left(-4\right)\pm \sqrt{\left(-4\right)^2-4\c* \:2\left(-9\right)}}{2\c* \:2}\\\\\sqrt{\left(-4\right)^2-4\cdot \:2\left(-9\right)}\\\\

Apply rule,

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Apply exponent rule,

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(-4)^{2} =4^{2}

\sqrt{4^2+4\cdot \:2\cdot \:9}

Multiply the numbers :

4*2*9=72\\\\\sqrt{4^2+4\cdot \:2\cdot \:9}\\\\4^{2} =16\\\\=\sqrt{16+72}\\\\

Add the number  =\sqrt{88}

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