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iren2701 [21]
3 years ago
7

Order the group of parabolas from widest to narrowest.

Mathematics
1 answer:
Mamont248 [21]3 years ago
6 0

Answer:

\large\boxed{y=\dfrac{1}{4}x^2,\ y=-\dfrac{1}{2}x^2,\ y=\dfrac{3}{2}x^2}

Step-by-step explanation:

The equation of a parabola: y = ax²

The larger the value of |a|, the narrower the parabola.

We have the following coefficients a:

\left|\dfrac{1}{4}\right|=\dfrac{1}{4},\ \left|-\dfrac{1}{2}\right|=\dfrac{1}{2},\ \left|\dfrac{3}{2}\right|=\dfrac{3}{2},

We arrange the coefficients from the smallest to the largest:

\dfrac{1}{4}\

Therefore you have the answer:

y=\dfrac{1}{4}x^2,\ y=-\dfrac{1}{2}x^2,\ y=\dfrac{3}{2}x^2

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alexdok [17]

Answer:

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4 0
3 years ago
Find the value of c that makes x^2–6x + c a perfect square trinomial and write as a binomial squared.
denpristay [2]

Answer: 9

Step-by-step explanation:

Given

The function is x^2-6x+c

To make it a perfect square, compare it with (a-b)^2=a^2+b^2-2ab

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x=a,\\-6x=-2ab\\\\\therefore b=3

So, c must be square of b i.e. 9

x^2-6x+c\Rightarrow x^2-6x+9\\\Rightarrow (x-3)^2

Therefore, value of c is 9.

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How can you tell that the data in the table is function or not?
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