M = 2.2 g = 2.2 x 10⁻³ kg, the mass of the bug.
r = 3.0 cm = 0.03 m, the radial distance from the center.
The angular speed is
ω = 280 rpm
= (280 rev/min)*(2π rad/rev)*(1/60 min/s)
= 29.3215 rad/s
The moment of inertia of the bug is
I = mr²
= (2.2 x 10⁻³ kg)*(0.03 m)²
= 1.98 x 10⁻⁶ kg-m²
Calculate the angular momentum of the bug.
J = Iω
= (1.98 x 10⁻⁶ kg-m²)*(29.3215 rad/s)
= 5.806 x 10⁻⁵ (kg-m²)/s
Answer: 5.806 x 10⁻⁵ (kg-m²)/s
<h3>
Answer:</h3>
20 seconds
<h3>
Explanation:</h3>
<u>We are given</u>;
- Power of the engine as 400 watts
- Force as 100 N
- Distance the object is lifted up as 80 m
We are required to determine the time taken.
- We need to know that power is the rate of work done
Therefore;
But, work done = Force × distance
Work done = 100 N × 80 m
= 8000 Joules
- Since , Power = Work done ÷ time
Then, time = Work done ÷ Power
Thus;
Time = 8000 J ÷ 400 W
= 20 s
Therefore, the time taken by the engine to lift the object is 20 seconds
Answer:
Distance
Explanation:
When using the length of the space between two points, the distance measures the length
They wouldn't stick because it wouldn't be as fast.