<span>θ=0.3sin(4t)
w=0.3cost(4t)(4)=1.2cost(4t)
a=-4.8sin(4t)
cos4t max will always be 1 (refer to cos graph), for same reason, sin4t will always be 0
therefore, wmax=1.2rad/s
vAmax=r*w=250*1.2=300mm/s
(may be different if your picture/radius is from a different picture)
adt=a*r=200*-4.8sin(4t)=0 (sin(4t)=0)
adn=r*w^2=200*1.2^2=288
ad= square root of adt^2+adn^2 = 288mm/s^2</span>
Answer:
a) 
b)
Explanation:
First we convert our minutes to hours so we work always in the same units.


Where we used the fact that 1 hour are 60 min, thus the multiplying factor is equal to 1 (not altering the time, just changing the units).
a) On the first part the motorist travels a distance
, and on the second part he travels
.
The total displacement is 
b) The average velocity is the relation between the total displacement and the time taken to cover it. Our total time is t=0.6h+0.25h+2.2h=3.05h, thus we have:

Power is energy per unit time. If he is powerful, it means he can spend more energy in short span of time, so option C ( i.e. <span>do more work in less time) is correct.</span>
Answer:
hello your question is incomplete hence I will give you a general answer on how a stunt cyclist performs his stunts successfully
answer ;
The stunt cyclist trying to perform some sort of stunt with the bicycle will be faced with some forces like the static fiction between the tires of the bicycle and wall and also a centripetal force.
In order to overcome the centripetal force the minimal grip of the bicycle must be equal to the weight and the speed at which the cyclist must go can be represented as :

Explanation:
The stunt cyclist trying to perform some sort of stunt with the bicycle will be faced with some forces like the static fiction between the tires of the bicycle and wall and also a centripetal force.
In order to overcome the centripetal force the minimal grip of the bicycle must be equal to the weight and the speed at which the cyclist must go can be represented as :

where ; r = radius of the tunnel where the stunt is to be performed
g = gravitational speed
u = coefficient of static friction