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goldenfox [79]
4 years ago
12

How long will it take a 400 W engine to lift a 100 N object up to a height of 80 m?

Physics
2 answers:
Norma-Jean [14]4 years ago
4 0
<h3>Answer:</h3>

20 seconds

<h3>Explanation:</h3>

<u>We are given</u>;

  • Power of the engine as 400 watts
  • Force as 100 N
  • Distance the object is lifted up as 80 m

We are required to determine the time taken.

  • We need to know that power is the rate of work done

Therefore;

  • Power = Work done ÷ time

But, work done  = Force × distance

  • Therefore; In this case;

Work done = 100 N × 80 m

                  = 8000 Joules

  • Since , Power = Work done ÷ time

Then, time = Work done ÷ Power

Thus;

Time = 8000 J ÷ 400 W

       = 20 s

Therefore, the time taken by the engine to lift the object is 20 seconds

Kitty [74]4 years ago
3 0

Answer:

The time will be 20 seconds

Explanation:

The work is:

W=F*d

where:

F=force[N]

d=distance[m]

W=100*80=8000[J]

The time will be given by:

t= Work/power

where:

work=work done by the force[J]

Power=work done in an interval of time [Watts]

t=8000/400

Analysis of units (J / J/s) = [s]

t=20[s]

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Ronch [10]

Answer:

1. G.P.E = 24 J

2. center of mass

Explanation:

Given the following data;

Mass = 2kg

Height, h = 1.2m

Acceleration due to gravity = 9.8 N/kg or m/s².

To find the gravitational potential energy;

Gravitational potential energy (GPE) is an energy possessed by an object or body due to its position above the earth.

Mathematically, gravitational potential energy is given by the formula;

G.P.E = mgh

Where;

  • G.P.E represents potential energy measured in Joules.
  • m represents the mass of an object.
  • g represents acceleration due to gravity measured in meters per seconds square.
  • h represents the height measured in meters.

Substituting into the formula, we have;

G.P.E = 2*1.2*9.8

G.P.E = 23.52 to 2 S.F = 24 Joules.

Translation kinetic energy is defined as the energy of a system due to the motion of the system’s center of mass. The center of mass is typically where the mass of the object or particle is concentrated.

6 0
3 years ago
the kinetic energy of an object with mass m moving with a velocity of 5 m/s is 25 j what will be its kinetic energy when its vel
Dmitriy789 [7]

Answer:

100 J, 225 J

Explanation:

The kinetic energy of an object is given by:

K=\frac{1}{2}mv^2

where

m is the mass of the object

v is the velocity of the object

In this problem, the initial kinetic energy of the object is

K = 25 J

Then, the velocity is doubled, which means

v' = 2v

Therefore, the new kinetic energy will be

K'=\frac{1}{2}m(2v)^2 = 4(\frac{1}{2}mv^2)=4K

Therefore, the kinetic energy has quadrupled:

K' = 4(25)=100 J

Later, the velocity is tripled, which means

v'' = 3v

Therefore, the new kinetic energy will be

K''=\frac{1}{2}m(3v)^2 = 9(\frac{1}{2}mv^2)=9K

Therefore, the kinetic energy has increased by a factor of 9:

K' = 9(25)=225 J

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Answer:

45°

Explanation:

The textbooks say that the maximum range for projectile motion (with no air resistance) is 45 degrees.

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