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goldenfox [79]
3 years ago
12

How long will it take a 400 W engine to lift a 100 N object up to a height of 80 m?

Physics
2 answers:
Norma-Jean [14]3 years ago
4 0
<h3>Answer:</h3>

20 seconds

<h3>Explanation:</h3>

<u>We are given</u>;

  • Power of the engine as 400 watts
  • Force as 100 N
  • Distance the object is lifted up as 80 m

We are required to determine the time taken.

  • We need to know that power is the rate of work done

Therefore;

  • Power = Work done ÷ time

But, work done  = Force × distance

  • Therefore; In this case;

Work done = 100 N × 80 m

                  = 8000 Joules

  • Since , Power = Work done ÷ time

Then, time = Work done ÷ Power

Thus;

Time = 8000 J ÷ 400 W

       = 20 s

Therefore, the time taken by the engine to lift the object is 20 seconds

Kitty [74]3 years ago
3 0

Answer:

The time will be 20 seconds

Explanation:

The work is:

W=F*d

where:

F=force[N]

d=distance[m]

W=100*80=8000[J]

The time will be given by:

t= Work/power

where:

work=work done by the force[J]

Power=work done in an interval of time [Watts]

t=8000/400

Analysis of units (J / J/s) = [s]

t=20[s]

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8 0
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Write a balanced equation for the decomposition of ammonium nitrate to form molecular nitrogen, molecular oxygen, and water. Exp
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The unbalanced reaction is

<em>a</em> NH₄NO₃   ⇒   <em>b</em> N₂ + <em>c</em> O₂ + <em>d</em> H₂O

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N = 2<em>a</em>, H = 4<em>a</em>, O = 3<em>a</em>

• products

N = 2<em>b</em>, O = 2<em>c</em> + <em>d</em>, H = 2<em>d</em>

<em />

Now we solve the system of equations,

2<em>a</em> = 2<em>b</em> … … … [1]

4<em>a</em> = 2<em>d</em> … … … [2]

3<em>a</em> = 2<em>c</em> + <em>d</em> … … … [3]

<em />

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<em>a</em> = <em>b</em>

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2<em>a</em> = <em>d</em>

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<em />

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• <em>d</em> = 2×2 = 4

So, the balanced reaction is

2 NH₄NO₃   ⇒   2 N₂ + O₂ + 4 H₂O

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