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2 years ago

A father pushes his child in a cart. The cart starts to move.

Physics

1 answer:

LuckyWell [14K]2 years ago

5 0

The potential energy of the car when it let go is 20,000 J.

The speed of the car at the bottom of the ramp is 20 m/s.

The given parameters;

<em>mass of the car, m = 100 kg</em>
<em>height of the car, h = 20 m</em>

<em />

The potential energy of the car is calculated as follows;

P.E = mgh

P.E = 100 x 10 x 20

P.E = 20,000 J

The speed of the car at the bottom of the ramp is calculated as follows;

$K.E = P.E\\\\\frac{1}{2} mv^2 = mgh\\\\v^2 = 2gh\\\\v = \sqrt{2gh} \\\\v = \sqrt{2 \times 10 \times 20} \\\\v = 20 \ m/s$

Learn more here:brainly.com/question/18597080

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<h2>Further Explanation </h2><h3>Gay-Lussac’s law </h3>

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Keywords: Gas law, Gay-Lussac’s law, pressure, volume, absolute temperature, ideal gas

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