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pentagon [3]
3 years ago
15

This diagram shows three horizontal forces acting on an object.

Physics
1 answer:
mixer [17]3 years ago
5 0

Answer:

14N

Explanation:

Hope it will help

Brainlists please

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When the atom's electrons step down to lower energy levels in a thin cloud of hot gas, what is produced?
Reika [66]

Answer: The correct answer is an emission line spectrum.

Explanation:

When the electrons are excited to the higher energy level, the energy is absorbed in this case.

When the electrons in the atom step down to lower energy levels in a thin cloud of hot gas then the radiation will emit.

The electron will lose energy in this case in the form of radiation. There will be an emission line spectrum.

8 0
3 years ago
Read 2 more answers
The wave length of violet light rounded to the nearest nanometer is a __ nm
nataly862011 [7]
Wavelength= speed / frequency 

so.....3× 10^8 / 7.26×10^14
= .413× 10^(-6)

in scientific notation= 4.13×10^(-7) 

in nanometer = 413 nm
6 0
3 years ago
If circuit A has twice the resistance of circuit B. The voltage is the same in each circuit.which circuit has the higher current
sladkih [1.3K]

Answer:

circuit b will have the higher current than circuit a

4 0
3 years ago
A small block with mass 0.0350 kgkg slides in a vertical circle of radius 0.550 mm on the inside of a circular track. During one
Lisa [10]

Answer:

 W_net = μ 5.58,   μ = 0.1     W_net = 0.558 J

Explanation:

The work is defined by the related

          W = F. d ​​= F d cos θ

where bold indicates vectors.

In the case, the work of the friction force on a circular surface is requested.

The expression for the friction force is

              fr = μ N

the friction force opposes the movement, therefore the angle is 180º and the cos 180 = -1

               W = - fr d

the path traveled half the length of the circle

               L = 2 π R

               d = L / 2

               d = π R

we substitute

                 W = - μ N d

Total work is initial to

                W_neto = - μ π R (N_b - N_a)

let's calculate

                W_net = - μ π 0.550 (0.670 - 3.90)

                W_net = μ 5.58

for the complete calculation it is necessary to know the friction coefficient, if we assume that μ = 0.1

                W_net = 0.1 5.58

                W_net = 0.558 J

7 0
3 years ago
Two balls have the same mass of 5.00 kg. Suppose that these two balls are attached to a rigid massless rod of length 2L, where L
olga_2 [115]

Answer:

Explanation:

Given

mass of balls m= 5 kg

N=45.6 rev/s

angular velocity \omega =2\pi N=286.55 rad/s

Length of Rod 2L=1.1 m

Tension in the Second half of rod

T_2=m\omega ^2(2L)=2m\omega ^2L

T_2=5\times (286.55)^2\times 1.1

T_2=451.609 kN

For First Part

T_1-T_2=m\omega ^2L

T_1=T_2+m\omega ^2L

T_1=3 m\omega ^2L

T_1=3\times 5\times (286.55)^2\times 0.55

T_1=677.41 kN

7 0
3 years ago
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