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4 years ago

What is the formula for calculating density?

2 answers:

6 0

Density can be determined by the mass of an object and how much it takes up space (volume). It is represented by the formula D = M/V where D is the density in kg/m^3 or lb/ft^3, M is the mass in kg or lb and V is the volume in m^3 or ft^3. The answer would be A. For example, you are given the mass of an object of 40.5kg and a volume of 15m^3. Find its density.

D = M/V
D = (40.5 kg) / (15 m^3)
D = 27/10 or 2.7 kg/m^3

Zarrin [17]4 years ago

3 0

Answer:

My answer is A.

Explanation:

by using a density triangle, you would have to cover up the density and then it will show you, m over v. so that means you would have to divide.

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A) $5.0\cdot 10^{-11} m$

The energy of an x-ray photon used for single dental x-rays is

$E=25 keV = 25,000 eV \cdot (1.6\cdot 10^{-19} J/eV)=4\cdot 10^{-15} J$

The energy of a photon is related to its wavelength by the equation

$E=\frac{hc}{\lambda}$

where

$h=6.63\cdot 10^{-34}Js$ is the Planck constant

$c=3\cdot 10^8 m/s$ is the speed of light

$\lambda$ is the wavelength

Re-arranging the equation for the wavelength, we find

$\lambda=\frac{hc}{E}=\frac{(6.63\cdot 10^{-34} Js)(3\cdot 10^8 m/s)}{4\cdot 10^{-15}J}=5.0\cdot 10^{-11} m$

B) $2.0\cdot 10^{-11} m$

The energy of an x-ray photon used in microtomography is 2.5 times greater than the energy of the photon used in part A), so its energy is

$E=2.5 \cdot (4\cdot 10^{-15}J)=1\cdot 10^{-14} J$

And so, by using the same formula we used in part A), we can calculate the corresponding wavelength:

$\lambda=\frac{hc}{E}=\frac{(6.63\cdot 10^{-34} Js)(3\cdot 10^8 m/s)}{1\cdot 10^{-14}J}=2.0\cdot 10^{-11} m$

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3 years ago

Two objects experienced the same displacement in the same amount of time. The two objects must have the same -

nikdorinn [45]

If two object experiences the same displacement at the same time, the two objects must have the same average velocity.

The average velocity of an object is defined as the change in displacement per change in time of motion. This can be written as follows;

$avg. \ velocity = \frac{\Delta \ displacement }{\Delta \ time} \\\\V = \frac{\Delta \ x}{\Delta t}$

If two object experiences the same displacement at the same time, it means that the change in displacement with time is constant.

$\frac{\Delta x_1}{\Delta t_1} = \frac{\Delta x_2}{\Delta t_2} = V_{avg}$

Thus, we can conclude that if two object experiences the same displacement at the same time, the two objects must have the same average velocity.

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