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zepelin [54]
3 years ago
11

What is the area of a sector with a central angle of 2π/9 radians and a radius of 16.7 ft?

Mathematics
2 answers:
Y_Kistochka [10]3 years ago
8 0

Answer:

Area of the sector is 97.30 square feet.

Step-by-step explanation:

The area of the sector is given by

A=(\frac{\theta}{2})r^2

Plugging the known values in this formula to find the area of the sector

A=(\frac{2\pi/9}{2})(16.7)^2\\\\A=\frac{2\pi}{18}\cdot16.7^2

Use the value of π as 3.14

A=\frac{2\cdot3.14}{18}\cdot16.7^2

Simplifying, we get

A=97.3016

Rounded to the nearest hundredth, we get

A=97.30

navik [9.2K]3 years ago
7 0

Answer:

97.30

Step-by-step explanation:

I can confirm that this is the correct answer. :D

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The total distance walked by Paulo is 3750 feet.

Step-by-step explanation:

Here the four points are<em> (-2,1) (-2,-7) (5,-7) (5,1)</em>

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Moving from stop B to C, only the x coordinate changes,

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It is given that <em>1 unit = 125 feet</em>

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The total distance walked by Paulo is 3750 feet.

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Answer:

The attachment shows ΔBAC ~ ΔBDA

Step-by-step explanation:

You want segment AB to be part of two similar, but not congruent, triangles. One way to do that is to make AB the hypotenuse of one triangle and the leg of another.

It is convenient to construct these triangles using point M as the arbitrary midpoint of the hypotenuse of the larger triangle. (We don't know the coordinates of M—we just know it is on the perpendicular bisector of AB.) BC is a diameter of circle M, and AD is the altitude of ΔABC.

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