Answer:

Step-by-step explanation:
<u>Probabilities</u>
The question describes an event where two counters are taken out of a bag that originally contains 11 counters, 5 of which are white.
Let's call W to the event of picking a white counter in any of the two extractions, and N when the counter is not white. The sample space of the random experience is

We are required to compute the probability that only one of the counters is white. It means that the favorable options are

Let's calculate both probabilities separately. At first, there are 11 counters, and 5 of them are white. Thus the probability of picking a white counter is

Once a white counter is out, there are only 4 of them and 10 counters in total. The probability to pick a non-white counter is now

Thus the option WN has the probability

Now for the second option NW. The initial probability to pick a non-white counter is

The probability to pick a white counter is

Thus the option NW has the probability

The total probability of event A is the sum of both


See attached for the solution
Answer:
No.
Step-by-step explanation:
It is not because 20 is not a perfect square.
Answer: 2,3, and the last one.... I think
Step-by-step explanation:
Answer:
The correct option is parallelogram ABCD is a rhombus, because the diagonal bisects two angles
Step-by-step explanation:
In triangle ABD:
∠B = ∠D
Thus AB=AC by the property of opposite sides of equal angles are equal
In triangle CBD
∠B = ∠D
Thus CB=CD by the property of opposite sides of equal angles are equal
Thus all four sides of quadrilateral ABCD are equal
And diagonal BD bisects the angles
So, it is a rhombus
Therefore the correct option is parallelogram ABCD is a rhombus, because the diagonal bisects two angles....