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steposvetlana [31]
3 years ago
14

Give an example of an addition problem in which you would and would not group the addends differently to add

Mathematics
1 answer:
lubasha [3.4K]3 years ago
7 0
Im confused can you pit that in better understanding
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X + y = -1<br> X - y = 7
enyata [817]
1: Solve for either x or y in one of the equations. So x + y = -1 is y = -x -1
2: substitute the new equation in the opposite equation. So x - (-x - 1) = 7
3: distribute the negative. X + x + 1 = 7
4: combine like terms. 2x + 1 = 7
5: solve for x. Subtract 1 on both sides. 2x = 6
6: divide by 2 to get x by itself. X = 3
7: plug the new value of x into one of the ORIGINAL equations. 3 + y = -1
8: solve for y. Subtract 3 on both sides.
Y = -4
9: the solution is written as (x,y) so the solution would be (3, -4)
4 0
3 years ago
Using the properties of absolute values, simplify the expression x×|x|, if it is known that:
Westkost [7]

Answer:

  • x ≥ 0: x|x| = x²
  • x < 0: x|x| = -x²

Step-by-step explanation:

<u>For x ≥ 0</u>

  |x| = x

so

  x|x| = x(x) = x²

<u>For x < 0</u>

  |x| = -x

so

  x|x| = x(-x) = -x²

7 0
3 years ago
Find all six trigonometric ratios for the triangle shown. Show all work. In order to enter
hichkok12 [17]

Answer:

<h2>use the required formulas please !</h2>
7 0
3 years ago
<img src="https://tex.z-dn.net/?f=3%20%20%5Cfrac%7B1%7D%7B2%7D%20%20%2B%202%20%5Cfrac%7B1%7D%7B4%7D%20%20-%201%20%5Cfrac%7B1%7D%
Svetach [21]

Answer:

Step-by-step explanation:

Step 1: Convert into improper fractions

Step 2: Find  least common denominator and find equivalent fractions

Step 3 : Do the required operation

3\frac{1}{2}+2\frac{1}{4}-1\frac{1}{2}=\frac{7}{2}+\frac{9}{4}-\frac{3}{2}\\

Least common denominator of 2 , 4 = 4

   =\frac{7*2}{2*2}+\frac{9}{4}-\frac{3*2}{2*2}\\\\=\frac{14}{4}+\frac{9}{4}-\frac{6}{4}\\\\=\frac{14+9-6}{4}\\\\=\frac{17}{4}\\\\=4\frac{1}{4}

5 0
3 years ago
Find the Lowest Common Multiple (LCM) of 21, 63 and 105.
Sedaia [141]
A ) 15 I think because it the lowest number!
4 0
3 years ago
Read 2 more answers
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