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KengaRu [80]
4 years ago
7

8/10 is iqual to 4/5

Mathematics
2 answers:
yan [13]4 years ago
5 0
Yes, that is correct because if you want to reduce it you divide 8 by 2 and 10 by 2 and you get 4/5
Sauron [17]4 years ago
4 0
Yes, that is correct because if you want to reduce it you divide 8 by 2 and 10 by 2 and you get 4/5
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In the diagram below, the area of $\triangle BCD$ is 60. What is the length of side $\overline{BC}$?
Phantasy [73]

Area of triangle = 1/2 bh

60 = 1/2 (15) h

8 = h

Quadrilateral area = h x (b1 + b2)/2 = 8 x (15+9)/2 = 96 sq units

96 -60 = triangle BAD area = 36 sq units

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3 years ago
A scientist wants to estimate the number of roads living near a lake.
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7 0
3 years ago
PLEASE HURRY AND SOLVE!!!!
MissTica

Answer:

The constant of proportionality is 6

Step-by-step explanation:

Recall the equation for direct variation is y=kx where y varies directly with x and k is the constant of proportionality. If we take any listed coordinate point, we can determine the value of k. I will use (20,120) as an example:

y=kx\\\\120=k(20)\\\\6=k

Therefore, the constant of proportionality is 6

6 0
2 years ago
A group of students where asked about the number of e-mails they each send that day. The results are: 0, 1, 1, 2, 3, 3, 4, 4, 6,
valkas [14]

Answer:

Choice D

Step-by-step explanation:

After writing the data down seperate the values according to the x-axis on the graphs. You will find that 6 people chose between 0 to 3, 4 people chose between 4 to 7, 3 people chose between 8 to 11 and 2 people chose between 12 to 15.

6 0
3 years ago
Od<br> 2<br> (<br> 2 7 1-3<br> 1 3 1-2<br> 6:1-6<br> b =<br> d =<br> IDONE
Lena [83]

Answer:

a = \boxed{1},\: b=\boxed{0}\\\\c=\boxed{0},\: d=\boxed{1}

Step-by-step explanation:

  • \begin{bmatrix} 2 & 7\\\\1 & 3\end{bmatrix}\:\begin{bmatrix} -3 & 7\\\\1 & -2\end{bmatrix}=\begin{bmatrix} a & b\\\\c & d\end{bmatrix}

  • Multiply both the matrices on left side, we find:

  • \begin{bmatrix} 2(-3)+7(1) & 2(7)+7(-2)\\\\1(-3)+3(1) & 1(7)+3(-2)\end{bmatrix}=\begin{bmatrix} a & b\\\\c & d\end{bmatrix}

  • \rightarrow\begin{bmatrix} -6+7 & 14-14\\\\-3+3 & 7-6\end{bmatrix}=\begin{bmatrix} a & b\\\\c & d\end{bmatrix}

  • \rightarrow\begin{bmatrix} 1 & 0\\\\0 & 1\end{bmatrix}=\begin{bmatrix} a & b\\\\c & d\end{bmatrix}

  • Comparing the corresponding elements of both the matrices on both sides, we find:

  • a = \boxed{1},\: b=\boxed{0},\:c=\boxed{0},\: d=\boxed{1}
7 0
3 years ago
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