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hjlf
4 years ago
10

You have been hired by Beta Airlines to help them with their flight prices. You are to create a 10 x 10 2D array (also called a

matrix) that holds the prices of their domestic flights between Atlanta and Hawaii. Your program should fill the matrix with random values between $99 and $1999 and allow a user to enter a price that matches their preferred cost for the flight. You should then process the 2D array and return whether or not a price in the array matches their requested price (exactly matches).
Computers and Technology
1 answer:
AveGali [126]4 years ago
4 0

Answer:

See explaination

Explanation:

//Array to store prices

INT PRICE[10][10]

//Loop through 2d array

FOR I FROM 0 TO 10

FOR J FROM 0 TO 10

//Populate a random int

PRICE[I][J] = RANDOM_INT(99,1999)

PRINT(PRICE[I][J]+" ")

PRINT()

//Prompt user for desired price

COST = READ_INPUT('Please enter your desired flight price: ')

//Variable to store if a match is found

MATCH = FALSE

//Loop through all ints in price

FOR I FROM 0 TO 10

FOR J FROM 0 TO 10

//Compare price with Cost

IF PRICE[I][J]==COST

MATCH = TRUE

BREAK

//Check if match is true

IF MATCH = TRUE

PRINT('A flight was found for that price, have a safe trip!')

ELSE

PRINT('No flight was found for that price, please try a new price.')

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2 years ago
You are given a list of n positive integers a1, a2, . . . an and a positive integer t. Use dynamic programming to design an algo
Anna11 [10]

Answer:

See explaination for the program code

Explanation:

The code below

Pseudo-code:

//each item ai is used at most once

isSubsetSum(A[],n,t)//takes array of items of size n, and sum t

{

boolean subset[n+1][t+1];//creating a boolean mtraix

for i=1 to n+1

subset[i][1] = true; //initially setting all first column values as true

for i = 2 to t+1

subset[1][i] = false; //initialy setting all first row values as false

for i=2 to n

{

for j=2 to t

{

if(j<A[i-1])

subset[i][j] = subset[i-1][j];

if (j >= A[i-1])

subset[i][j] = subset[i-1][j] ||

subset[i - 1][j-set[i-1]];

}

}

//returns true if there is a subset with given sum t

//other wise returns false

return subset[n][t];

}

Recurrence relation:

T(n) =T(n-1)+ t//here t is runtime of inner loop, and innner loop will run n times

T(1)=1

solving recurrence:

T(n)=T(n-1)+t

T(n)=T(n-2)+t+t

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,,

,

T(n)=T(n-n-1)+(n-1)t

T(n)=T(1)+(n-1)t

T(n)=1+(n-1)t = O(nt)

//so complexity is :O(nt)//where n is number of element, t is given sum

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