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3 years ago

What is the value of the exponential expression 16 1/2

Mathematics

1 answer:

Oksana_A [137]3 years ago

3 0

<h3>♫ - - - - - - - - - - - - - - - ~Hello There!~ - - - - - - - - - - - - - - - ♫</h3>

➷ Anything to the power of a half means you square root it

The square root of 16 is 4

Therefore, your answer is 4

➶ Hope This Helps You!

➶ Good Luck (:

➶ Have A Great Day ^-^

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Need to find the sum of 50

Bumek [7]

Answer:

4600

Step-by-step explanation:

This is an arithmetic sequence with common difference d between consecutive terms.

d = - 2 - (- 6) = 2 - (- 2) = 6 - 2 = 4

The sum to n terms of an arithmetic sequence is

$S_{n}$ = $\frac{n}{2}$ [ 2a + (n - 1)d ]

where a is the first term

here a = - 6, d= 4 and n = 50, hence

$S_{50}$ = $\frac{50}{2}$ [ (2 × - 6) + (49 × 4) ]

= 25 ( - 12 + 196 )

= 25 × 184

= 4600

6 0

3 years ago

4. What is the system of equations that describes the following graph?

GarryVolchara [31]

Answer:

The system of inequalities is

$y$

$y>0.25x$

Step-by-step explanation:

step 1

Find the equation of the dashed line with negative slope

The line passes through the points

(0,-2) and (-2,0)

Find the slope

$m=(0+2)/(-2-0)=-1$

Find the equation of the line in slope intercept form

$y=mx+b$

we have

$m=-1\\b=-2$

substitute

$y=-x-2$

The solution of the inequality is the shaded area below the dashed line

therefore

The equation of the inequality A is

$y$

step 2

Find the equation of the dashed line with positive slope

The line passes through the points

(0,0) and (4,1)

Find the slope

$m=(1-0)/(4-0)=0.25$

Find the equation of the line (direct variation)

$y=kx$

we have

$k=0.25$

substitute

$y=0.25x$

The solution of the inequality is the shaded area above the dashed line

therefore

The equation of the inequality B is

$y>0.25x$

therefore

The system of inequalities is

$y$

$y>0.25x$

4 0

3 years ago

How does adding the log together automatically mean that it is a factorial?

andreyandreev [35.5K]

Answer: The answer is given below.

Step-by-step explanation: We are given an equality involving logarithm and we are to show the implication of L.H.S. to R.H.S.

We will be using the following two properties of logarithm:

$(i)~\log_ba=\dfrac{1}{\log_ab},\\\\\\(ii)~log_ab+\log_ac=\log_a(bc).$

The proof is as follows:

$L.H.S.\\\\\\=\dfrac{1}{\log_2N}+\dfrac{1}{\log_3N}+\dfrac{1}{\log_4N}+\cdots+\dfrac{1}{\log_{100}N}\\\\\\=\log_N2+\logN3+\log_N4+\cdots+\log_N100\\\\=\log_N\{2.3.4...100\}\\\\=\log_N\{1.2.3.4...100\}\\\\=\log_N{100!}\\\\=\dfrac{1}{\log_{100!}N}\\\\=R.H.S.$