Good evening
x^0+y^0 for x=3 and y=2
First thing we need to do is to replace their value
3^0+2^0
Remember: Any number that raised to the zero power equal 1
so now we have
3^0=1 and y^2=1
1+1
= 2
I hope that's help :0
Any Questions /
Answer:
Step-by-step explanation:
g(-1) = 4(-1) - 3 = -4 -3 = -7
f(-7) = (-7)^2 + 3 = 49 + 3 = 52
Answer is D
Answer:
not sure but I think it is this
Solve the equation replacing x with 2 and the 6:
-2^2 + 2(2) + 2 = 4 + 4 + 2 =10
-6^2 + 2(6) + 2 = 36 + 12 + 2 = 50
Difference between the answers: 50-10 = 40
Difference between 2 and 6 = 6-2 = 4
Average rate of change = 40/4 = 10
The answer is 10
