Math help

Mathematics

2 answers:

DIA [1.3K]2 years ago

8 0

Answer:

B $240.00

Step-by-step explanation:

thats the correct answer

Lelechka [254]2 years ago

8 0

I’ll assume the interest compounds annually (once a year).

Use A=P(1+r/n)^nt to solve!

A = Amount after time
P = Initial value
t = Time in years
r = Rate
n = Number of compounds(¿?)

A=200(1+0.08/1)^1x3

There is $251.94 in the account after three years!

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Please help!! What is the solution to the quadratic inequality? 6x2≥10+11x

fredd [130]

Answer:

The solution of the inequation $6\cdot x^{2} \geq 10 + 11\cdot x$ is $\left(-\infty,-\frac{2}{3}\right]\cup\left[\frac{5}{2},+\infty\right)$ .

Step-by-step explanation:

First of all, let simplify and factorize the resulting polynomial:

$6\cdot x^{2} \geq 10 + 11\cdot x$

$6\cdot x^{2}-11\cdot x -10 \geq 0$

$6\cdot \left(x^{2}-\frac{11}{6}\cdot x -\frac{10}{6} \right)\geq 0$

Roots are found by Quadratic Formula:

$r_{1,2} = \frac{\left[-\left(-\frac{11}{6}\right)\pm \sqrt{\left(-\frac{11}{6} \right)^{2}-4\cdot (1)\cdot \left(-\frac{10}{6} \right)} \right]}{2\cdot (1)}$