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masha68 [24]
3 years ago
14

Math help

Mathematics
2 answers:
DIA [1.3K]3 years ago
8 0

Answer:

B $240.00

Step-by-step explanation:

thats the correct answer

Lelechka [254]3 years ago
8 0
I’ll assume the interest compounds annually (once a year).

Use A=P(1+r/n)^nt to solve!

A = Amount after time
P = Initial value
t = Time in years
r = Rate
n = Number of compounds(¿?)

A=200(1+0.08/1)^1x3

There is $251.94 in the account after three years!

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HELP please.
Delvig [45]

Answer:

Q1: \frac{3}{4}

Q2: \frac{83}{100}

Step-by-step explanation:

Q1: 12 : 16 = 3 : 4 = \frac{3}{4}

Q2: 8.3 : 10 = \frac{83}{100}

3 0
3 years ago
An element with mass 670 grams decays by 27.3% per minute. How much of the element is remaining after 9 minutes, to the nearest
ArbitrLikvidat [17]
There will be 38 grams remaining.

The equation would be of the form
y = a(1+r)ˣ, where a is the initial value, r is the rate as a decimal number, and x is the amount of time.  Using our values from the problem, we have:

y = 670(1-0.273)^9 = 670(0.727)^9 = 38
6 0
3 years ago
Read 2 more answers
Helppppppppppppppppppp me Write this rate as a unit rate. 7/5 miles 2/3 hour
malfutka [58]

Answer: Your answer is 3.5 miles per hour.

Step-by-step explanation:

7 0
3 years ago
¿Como se realizan ecuaciones de primer grado?
Law Incorporation [45]
5^0=1

Any exponent to zero power equals 1
7 0
3 years ago
Car A, traveling at a constant 10 m/s, crosses the start line 3 seconds before Car B, who is traveling at a constant 15 m/s. At
Margaret [11]
The distance between Car A and car B,When Car A crosses the start line is:
distance =speed car B* time
distance=(15 m/s)(3 s)=45 m
 
Distance traveled by car A =x,  (when the car B is at the same distance from the start line)
time of car A=t

x=10 m/st  ⇒    x=10t    (1)

Distance traveled by car B=x
time of car B=t-3

x=15(t-3)  (2)

With the equations (1) and (2) we make a system of equations:

x=10t
x=15(t-3)

We solve this system of equations:

10t=15(t-3)
10t=15t-45
-5t=-45
t=-45 / -5
t=9

t-3=9-3=6

x=10 t=10 (9)=90

Answer: The time would be 9 seconds for Car A and 6 seconds for car B and the distance would be 90 meters.
8 0
3 years ago
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