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Stels [109]
3 years ago
13

Determine if the following point is a solution to the system of equations:

Mathematics
1 answer:
Hunter-Best [27]3 years ago
3 0

Answer:

Yes it is

Step-by-step explanation:

3 + 4 =7

4 = 2(3) - 2

4 = 6 - 2

4 = 4

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0.66666666666 as a decimal

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There are 16 girls in a school club. The number of girls is four more than twice the number of boys. Find the number of boys
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Bill spent 50% of his savings on school supplies, then he spent 50% of what was left on lunch. If he had $6 left after lunch, ho
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What is the area of this square the height is 4 in the width is 4
puteri [66]

Answer;

64

Step-by-step explanation:

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3 0
2 years ago
The combined SAT scores for the students at a local high school are normally distributed with a mean of 1479 and a standard devi
kotykmax [81]

Answer:

0.35% of students from this school earn scores that satisfy the admission requirement.

Step-by-step explanation:

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

The combined SAT scores for the students at a local high school are normally distributed with a mean of 1479 and a standard deviation of 302.

This means that \mu = 1479, \sigma = 302

The local college includes a minimum score of 2294 in its admission requirements. What percentage of students from this school earn scores that satisfy the admission requirement?

The proportion is 1 subtracted by the pvalue of Z when X = 2294. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{2294 - 1479}{302}

Z = 2.7

Z = 2.7 has a pvalue of 0.9965

1 - 0.9965 = 0.0035

0.0035*100% = 0.35%

0.35% of students from this school earn scores that satisfy the admission requirement.

6 0
3 years ago
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