JK where T is the midpoint. J >>>>> T >>>>> K.
JK = 5x - 3
JT = 2x + 1
Because T is the midpoint, it means that JT = TK
So, JT + TK = JK
(2x + 1) + (2x + 1) = 5x - 3
4x + 2 = 5x - 3
4x - 5x = -3 - 2
-x = -5
x = 5
JK = 5x - 3
JK = 5(5) - 3
JK = 25 -3
JK = 22
The length of JK is 22.
So first you will need to multiply 9 by 4. You get 36. Now you need to add the 10 percent and you get 39.6! That's the answer!
Your answer should be 3a^2 + 5x + 9
Answer:
C. Median
Step-by-step explanation:
If both sides are <em>symmetrical,</em> then there is no need to try and find the mean or anything because you already have the middle point and no outliers. <u>If there were outliers it'd be different</u>, unless the outliers were symmetrical with the rest of it, then the median would still be a good option.
Answer: False.
Step-by-step explanation:
There does not exist a "quarter circle" as a circle with a radius of 4 units, the only notable circle that does exist is the unit circle, that is the circle where the radius is equal to 1, represented by the equatin x^2 + y^2 = 1
The term "quarter circle" actually does refer to a fourth part of a circle, not to a circle of radius 4.
So the statement is false
