All categories

3 years ago

Please answer all of this!!!! will give brainliest!!!

Mathematics

1 answer:

timurjin [86]3 years ago

8 0

Answer:

I can't see it that well. sorry!

Step-by-step explanation:

You might be interested in

Find the exact value by using a half angle identity.tan 75°

kramer

The trigonometric function is given as

$\tan 75^{\circ}$

Apply the half angle identity to find the value of tan 75 ,

$\tan (\frac{u}{2})=\frac{\sin u}{1+\cos u}$

Here,

$\tan (\frac{150^{\circ}}{2})=\frac{\sin150^{\circ}}{1+cos150^{\circ}}$ $\tan (75^{\circ})=\frac{\frac{1}{2}}{1-\frac{\sqrt[]{3}}{2}}=\frac{\frac{1}{2}}{\frac{2-\sqrt[]{3}}{2}}^{}$ $\tan 75^{\circ}=\frac{1}{2-\sqrt[]{3}}$

Now rationalize the function.

$\tan 75^{\circ}=\frac{1}{2-\sqrt[]{3}}\times\frac{2+\sqrt[]{3}}{2+\sqrt[]{3}}=\frac{2+\sqrt[]{3}}{4-3}=\frac{2+\sqrt[]{3}}{1}$

Again simplify the trigonometric function,

$\tan 75^{\circ}=2+1.732=3.732$

Hence the answer is 3.732.

5 0

1 year ago

Someone please help me!!!! I’ll make you brainlist

iren [92.7K]

Answer:

Volume of Pipe is 226 ft³.

Step-by-step explanation:

Given:

Cylindrical Shape Pipe having

Height = 18 ft

Diameter = 4 ft

∴ $Radius =\frac{Diameter}{2}=\frac{4}{2}=2\ ft$

To Find:

Volume of Pipe = ?

Solution:

Formula for Volume of Cylinder is given by

$\textrm{Volume of Cylinder}=\pi (Radius)^{2} \times Height$

Substituting the given values we get

$\textrm{Volume of Pipe}=3.14\times 2^{2} \times 18\\\\\textrm{Volume of Pipe}=226.08\\\\\therefore \textrm{Volume of Pipe}=226\ ft^{3}$

Volume of Pipe is 226 ft³.

8 0

3 years ago

D. Lauren and Gina's mother told her daughters they can

goblinko [34]

Answer:

4 minutes left

Step-by-step explanation:

20 - 16 = 4

4 0

3 years ago

Read 2 more answers

Solve the following proportion for u.<br> 17/13=u/4

icang [17]

Answer:

u=5.23

Step-by-step explanation:

$\frac{17}{13} =\frac{u}{4}\\13u=68~by~cross-multiplication\\u=5.23~rounded~to~the~nearest~hundreds$

5 0

3 years ago

Section 5.2 Problem 17:

Elina [12.6K]

This DE has characteristic equation

$4r^2 - 12r + 9r = (2r - 3)^2 = 0$

with a repeated root at r = 3/2. Then the characteristic solution is

$y_c = C_1 e^{\frac32 x} + C_2 x e^{\frac32 x}$

which has derivative

${y_c}' = \dfrac{3C_1}2 e^{\frac32 x} + \dfrac{3C_2}2 x e^{\frac32x} + C_2 e^{\frac32 x}$

Use the given initial conditions to solve for the constants:

$y(0) = 3 \implies 3 = C_1$

$y'(0) = \dfrac52 \implies \dfrac52 = \dfrac{3C_1}2 + C_2 \implies C_2 = -2$

and so the particular solution to the IVP is

$\boxed{y(x) = 3 e^{\frac32 x} - 2 x e^{\frac32 x}}$

8 0

2 years ago