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nikdorinn [45]
3 years ago
9

A .5 kg toy train car moving forward at 3 m/s collides with and sticks to a .8 kg toy car that is traveling at 2 m/s what is the

final velocity of the two cars round to the nearest 10th
Physics
1 answer:
Viktor [21]3 years ago
4 0
Here we have perfectly inelastic collision. Perfectly inelastic collision is type of collision during which two objects collide, stay connected and momentum is conserved. Formula used for conservation of momentum is:
m_{1} * v_{1} + m_{2} * v_{2} = m_{1} * v'_{1}+ m_{2} * v'_{2}

In case of perfectly inelastic collision v'1 and v'2 are same.

We are given information:
m₁=0.5kg
m₂=0.8kg
v₁=3m/s
v₂=2m/s
v'₁=v'₂=x

0.5*3 + 0.8*2 = 0.5*x + 0.8*x
1.5 + 1.6 = 1.3x
3.1 = 1.3x
x = 2.4 m/s
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Nezavi [6.7K]

Use Net Force Equation.

Fnet = F1 + F2 + F3 + F4

In which the following main forces in play are:

F1 = Gravitational Force

F2 = Normal Force

F3 = Thrust Force

F4 = Air resistance

Since this is assumed to happen on a flat surface, the gravitational and normal forces cancel out. So we are left with:

Fnet = F(thrust) + F(air resistance)

Now we can use this equation to solve for the net force.

Fnet = 10N [right] + 7N [left]

Fnet = 10N [right] - 7N [right]

Fnet = 3N [right].

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3 years ago
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Answer:

use the mole concept

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svp [43]
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6 0
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Read 2 more answers
Guys please help me on the rest of the numbers
wel

Answer:

C. 100

D.3

E. 33.3

Explanation:

C. Mechanical Advantage=Load / Effort

= 200N

--------

100N

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8 0
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MAXImum [283]
Momentum = mass × velocity
360 = mass × 7.2
mass = 360/7.2 = 50 kg

Hope it helped!!
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