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JulsSmile [24]
4 years ago
13

What is the circle of least confusion?

Physics
1 answer:
Artist 52 [7]4 years ago
5 0

Answer and Explanation:

In optics, a CoC(Circle of Confusion) is defined the minimum cross section of a paraxial bundle of rays made by a lens which is sphero-cylindrical type and can be viewed as an optical spot, which do not converge perfectly at the focus  while a point source is being imaged due to spherical aberration.

The Circle of Confusion is also referred to as circle of indistinctness or a blur spot

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a nitrogen laser generates a pulse containing 10.0 mj of energy at a wavelength of 340.0 nm. how many photons are in the pulse?
Wewaii [24]

A nitrogen laser generates a pulse containing 10.0 mj of energy at a wavelength of 340.0 nm and has 1785 x 10¹⁹ photons in the pulse.

<h3>How many photons are in the pulse?</h3>

Energy of a single photon is

E=hcλ

E=6.626×10⁻³⁴ J s×3×108 m/s /340×10⁻⁹ m

E=6.31×10⁻¹⁹  J

Number of photons in the laser is

n=Total Energy/Energy per photon

n=10⁷×10⁻³J /5.90×10⁻¹⁹J/photon

n= 1785 x 10¹⁹ photons

To learn about photons, refer: brainly.com/question/20912241?referrer=searchResults

#SPJ4

6 0
2 years ago
A body in uniform velocity has zero acceleration why?
NikAS [45]
When the velocity is uniform, the velocity does not change. since acceleration is the rate of change in velocity, the acceleration will be zero when velocity is uniform
6 0
4 years ago
Read 2 more answers
One of the harmonics of a column of air in a tube that is open at one end and closed at the other has a frequency of 448 hz, and
Lelechka [254]
The general formula for the frequency of the nth-harmonic of the column of air in the tube is given by
f_n = n f_1
where f1 is the fundamental frequency.

In our problem, we have two harmonics, one of order n and the other one of order (n+1) (because it is the next higher harmonic), so their frequencies are
f_n = n f_1
f_{n+1} = (n+1) f_1
so their  difference is
f_{n+1} - f_n = (n+1) f_1 - n f_1 = (n+1-n) f_1 = f_1

So, the difference between the frequencies of the two harmonics is just the fundamental frequency of the column of air in the tube, which is:
f_1 = 576 Hz - 448 Hz = 128 Hz
7 0
4 years ago
A player kicks a soccer ball in a high arc toward the opponent's goal. At the highest point in its trajectory
____ [38]

At the highest point in its trajectory, the ball's acceleration is zero but its velocity is not zero.

<h3>What's the velocity of the ball at the highest point of the trajectory?</h3>
  • At the highest point, the ball doesn't go more high. So its vertical velocity is zero.
  • However, the ball moves horizontal, so its horizontal component of velocity is non - zero i.e. u×cosθ.
  • u= initial velocity, θ= angle of projection

<h3>What's the acceleration of the ball at the highest point of projectile?</h3>
  • During the whole projectile motion, the earth exerts the gravitational force with a acceleration of gravity along vertical direction.
  • But as there's no acceleration along vertical direction, so the acceleration along vertical direction is zero.

Thus, we can conclude that the acceleration is zero and velocity is non-zero at the highest point projectile motion.

Disclaimer: The question was given incomplete on the portal. Here is the complete question.

Question: Player kicks a soccer ball in a high arc toward the opponent's goal. At the highest point in its trajectory

A- neither the ball's velocity nor its acceleration are zero.

B- the ball's acceleration points upward.

C- the ball's acceleration is zero but its velocity is not zero.

D- the ball's velocity points downward.

Learn more about the projectile motion here:

brainly.com/question/24216590

#SPJ1

7 0
2 years ago
The Electrons in a beam are moving at 2.7x108 m/s in an electric field of 16000 N/C. What value must the magnetic field have if
kozerog [31]

Answer:

B = 0.07 mT

Explanation:

q = 1.6x10^-19 coulombs

for the electron to pass through the field undeflected the magnetic force acting on it must equal the electrical force due to the electric field

electric force = Eq = 16000 * 1.6x10^-19 newtons

magnetic force = qvB = 1.6x10^-19 * 2.7x10^8 * B

16000 * 1.6x10^-19 = 1.6x10^-19 * 2.7x10^8 * B

B = 0.07 mT (milli tesla)

8 0
3 years ago
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