From rest, a rock is dropped from a garage roof. The roof is 6.0 meters above ground level. The rock will reach the earth at a speed of 10.849 meters per second.
<h3>What is velocity?</h3>
The change of displacement with respect to time is defined as the velocity. Velocity is a vector quantity.
it is a time-based component. Velocity at any angle is resolved to get its component of x and y-direction.
Given data:
V(Final velocity)=? (m/sec)
h(height)= 6.0 m
u(Initial velocity)=0 m/sec
g(gravitational acceleration)=9.81 m/s²
Newton's third equation of motion:
Hence, the velocity of the rock as it hits the ground will be 10.849 m/sec.
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I think it’s the third one idk tho
Answer:
2 m/s²
Explanation:
the equations of motion are
S= ut +½at²
v² = u²+ 2as
v = u + at
s = (u+v)/2 × t
From the parameters given
u = 0m/s this is because it starts from rest
Distance (s) = 9m
Time (t) = 3s
Based on this the first equation would be used
s = ut + ½at²
Input values
9 = 0×3 + ½ × a x 3²
9 = 0 + 9a/2
9 = 4.5a
Divide both sides by 4.5
a = 9 / 4.5 m/s²
a = 2 m/s²
I hope this was helpful, please mark as brainliest
Answer:
Cart A
Explanation:
Momentum can be computed by finding the product of mass and velocity. To solve this, you can use the formula below to find the greatest momentum:
p = mv
where:
p = momentum (kgm/s) m = mass (kg) v = velocity (m/s)
Because carts are moving along with the weights, we need to consider the whole system. This means that you need to add in the masses and the mass of the cart.
<u>Cart A:</u>
m = 200kg + 0 kg = 200 kg
v = 4.8 m/s
p = 200kg x 4.8 m/s = 960 kg-m/s
<u>Cart B:</u>
m = 200kg + 20 kg = 220 kg
v = 4.0 m/s
p = 220kg x 4.0 m/s = 880 kg-m/s
<u>Cart C:</u>
m = 200kg + 40 kg = 240 kg
v = 3.8 m/s
p = 240kg x 3.8 m/s = 912 kg-m/s
<u>Cart D:</u>
m = 200kg + 60 kg = 260 kg
v = 3.5 m/s
p = 260kg x 3.5 m/s = 910 kg-m/s
As you can see, Cart A has the greatest momentum.
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