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navik [9.2K]
3 years ago
11

Is 1.3 less or greater then 1 3/5

Mathematics
2 answers:
allsm [11]3 years ago
8 0

Answer:

less

Step-by-step explanation:

because 1.3= 1 3/10 and 1 3/5 is equal to 1 6/10 there for it less than

Harlamova29_29 [7]3 years ago
6 0

Answer:

1.3 is less then 1 3/5  

Step-by-step explanation:

Because 1 3/5 is 1.6 and 1.6 is greater then 1.3 you can tell by the tenth place

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With which information can you construct more than one triangle?
madreJ [45]

Answer:

b & d

Step-by-step explanation:

6 0
2 years ago
(6m^3 -16m^2 + 15m - 40) / (2m^2 + 5)
Helen [10]
        6m3 - 16m2 + 15m - 40<span> Simplify ————————————————————— 2m2 + 5 </span>Checking for a perfect cube :

<span> 4.1 </span>  <span> 6m3 - 16m2 + 15m - 40</span>  is not a perfect cube 

Trying to factor by pulling out :

<span> 4.2 </span>     Factoring: <span> 6m3 - 16m2 + 15m - 40</span> 

Thoughtfully split the expression at hand into groups, each group having two terms :

Group 1:  15m - 40 
Group 2: <span> -16m2 + 6m3</span> 

Pull out from each group separately :

Group 1:   (3m - 8) • (5)
Group 2: <span>  (3m - 8) • (2m2)</span>
               -------------------
Add up the two groups :
              <span> (3m - 8)  • </span><span> (2m2 + 5)</span> 
<span>Which is the desired factorization</span>

<span>3m-8 is the answer</span>

4 0
3 years ago
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shusha [124]

Answer:

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Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
Maggie has $40 to buy a new dress and hair accessory for her school dance the dress she wants cost $35.75 the cost of her hair a
jonny [76]

Answer:

Yes Maggie has enough money to purchase the dress and hair accessory.

Step-by-step explanation:

Dress = $35.75

Hair accessory = $2.80

Total amount of money = $40

Does her have enough money?

Total Money in pocket - (Dress cost + hair accessory)

 $40.00 - ($35.75 + 2.80)

  $40.00 - ($36.00 + $3.00)     Round to the nearest dollar

  $40.00 - $39.00 = $1.00

Yes

8 0
2 years ago
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Ivahew [28]
45.827 or 45.83 dollars...............
8 0
3 years ago
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