Mad9AilraciePie,
The correct answer to this question is 60 tires in a bin.
Answer: 2nd diagram, explanation below
Step-by-step explanation:
Since it is 8 magnet students for 3 magic students, the second diagram is correct.
The second part, you would need to set up a system of equations:
Let m = magnet students and t = magic students
t + 25 = m
(8/3)t = m. Since m = m, substitute: t + 25 = (8/3)(t). Now solve for t: t = 8t/3 - 25,
t = (8t - 75)/3, in this step I turned 25 into 75/3 and place it with 8t so it doesn't change the value of the equation.
3t = 8t - 75, in this step I multiplied every term by 3 to eliminate the demoninator. Now I solve the final steps:
-5t = -75, 5t = 75
t = 15
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EDBC is a trapezoid
We know AC=8 and since the sides of an isosceles right triangle are in ratio
we conclude
We have a square so AD=ED=EF=4.
DB is the height of the trapezoid,
So the area of the trapezoid is
AFECB is the sum of two isosceles right triangles AFE + ABC so has area
That's a ratio of 8:24:8 or 1:3
That must mean that ADE and AFE each have area 8 as well.
Answer: 1/3
Answer:
3rd option
∠JGH= 1/2∠JIH
Step-by-step explanation:
This is because of the circle theorem that states that angle at center is equal to two times the equal at circumference
Answer:
2442
Step-by-step explanation:
The n th term of an arithmetic sequence is
= a₁ + (n - 1)d
where a₁ is the first term and d is the common difference
We require to find d knowing that 120 is the 44 th term, thus
= - 9 + 43d = 120 ( add 9 to both sides )
43d = 129 ( divide both sides by 43 )
d = 3
The sum to n terms of an arithmetic sequence is
= [ 2a₁ + (n - 1)d ], hence
= [ (2 × - 9 + (43 × 3) ]
= 22(- 18 + 129)
= 22 × 111 = 2442
OR
Since the first and last terms in the sequence are known, then
= ( first + last )
= 22(- 9 + 120) = 22 × 111 = 2442