The resulting composite function (f∘f)(x) is x⁴+2x²+2
When a function is written inside another function, it is known as a composite function
Given the function f(x)=x²+1,
(f∘f)(x) = f(f(x))
f(f(x)) = f(x²+1)
This means we will need to replace x with x²+1 in f(x) as shown:
f(x²+1) = (x²+1)²+1
Expand
f(x²+1) = x⁴+2x²+1+1
f(x²+1) = x⁴+2x²+2
Hence the resulting composite function (f∘f)(x) is x⁴+2x²+2
Learn more here: brainly.com/question/3256461
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Step-by-step explanation:
1. How many terms are in the expression?
The terms are sorted by looking at the sing/indicator in front of them. For this expression there are 4 terms
13x, -2y, -5x, and 8
2. Which terms are “like terms”?
13x and -5x are like terms.
3. Are there any constants? If so, what are they?
Yes there is a constant terms and it's 8
4. What are the variables in the expression?
The variables in this expression are x, and y
5. What are the coefficients in the expression?
Coefficients is the number in front of variables in this expression the coefficients are 13, -2, and -5
Answer:
its A
Step-by-step explanation:
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Answer:
see explanation
Step-by-step explanation:
consecutive even integers have a difference of 2 between them
for example 2, 4, 6 are 3 consecutive even integers
In general if we let the first integer be k then the next 2 integers are
k + 2 and k + 4
the sum of these equals 4 times the first integer, that is 4k, hence
k + k + 2 + k + 4 = 4k
3k + 6 = 4k ( subtract 3k from both sides )
6 = k
the 3 consecutive integers are
k = 6
k + 2 = 6 + 2 = 8
k + 4 = 6 + 4 = 10
that is 6, 8 and 10
note that sum = 6 + 8 + 10 = 24
and 4 × 6 = 24
confirming the sum of the 3 integers equals 4 times the first integer
