Find the real or imaginary solutions of the following equation by factoring y^3-512=0

In a random sample of students who took the SAT test, 427 had paid for coaching courses and the remaining 2733 had not. Calculat

Dvinal [7]

Answer:

The 95% confidence interval for the proportion of students who get coaching on the SAT is (0.1232, 0.147).

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of $\pi$ , and a confidence level of $1-\alpha$ , we have the following confidence interval of proportions.

$\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}$

In which

z is the z-score that has a p-value of $1 - \frac{\alpha}{2}$ .

427 had paid for coaching courses and the remaining 2733 had not.

This means that $n = 427 + 2733 = 3160, \pi = \frac{427}{3160} = 0.1351$

95% confidence level

So $\alpha = 0.05$ , z is the value of Z that has a p-value of $1 - \frac{0.05}{2} = 0.975$ , so $Z = 1.96$ .

The lower limit of this interval is:

$\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.1351 - 1.96\sqrt{\frac{0.1351*0.8649}{3160}} = 0.1232$

The upper limit of this interval is:

$\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.1351 + 1.96\sqrt{\frac{0.1351*0.8649}{3160}} = 0.147$

The 95% confidence interval for the proportion of students who get coaching on the SAT is (0.1232, 0.147).

8 0

3 years ago

A certain animated movie earned $1.1*10^9 in revenues at the box office. The movie lasts 9.1*10^1 minutes. How much revenue was

Vadim26 [7]

Answer:

$12,087,912.1

Step-by-step explanation:

$1.1*10^9$ is in scientific notation, to get this into normal number, we take the decimal point and move it "9" times to the right [whatever power of 10 we have, we move to right (if positive).] Then we fillup the rest with zeros.

So we have:

$1.1*10^9=1,100,000,000$

This is the revenue.

We do similar process for time:

$9.1*10^1=91$

This is the time , in minutes.

We want revenue PER minute, that means we divide the total revenue by total time, that would be:

$\frac{1,100,000,000}{91}=12,087,912.1$

The revenue earned per minute is $12,087,912.1

6 0

3 years ago

Write the number equal to 5 tens and 13 ones

serious [3.7K]

To find this out we have to add 5 tens and 13 ones.
5 tens is equal to
10 + 10 + 10 + 10 + 10 = 50

And 13 ones is equal to
1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 = 13

Now add 50 and 13
50 + 13 = 63

So your answer is 63

good Luck! :)

7 0

3 years ago

Draw two different perimeters of a rectangle with an area of 14 units. Name their dimensions.

Alenkasestr [34]

1:
Length: 7
Width:2
Perimeter: 18

2:
Length: 5
Width: 2.8
Perimeter: 15.6

8 0

3 years ago

Tameka bought 50 cans of soda ( cola, grape, and orange) to serve at a party. She has 8 more colas than grape sodas, and 3 less

Gwar [14]

Answer:

Orange = 12

Grape = 15

Cola = 23

Step-by-step explanation:

Turning this into equations you can give each soda a variable

Cola = C | Grape = G | Orange = R

Then you get:

8 + G = C

R + 3 = G

C + G + R = 50

We want to get a variable all by itself in an equation so first I'm going to put the second equation (R + 3 = G) in the first (8 + G = C) by replacing the G to get

8 + (R + 3) = C Combine the variables 11 + R = C and put that new equation into the last equation

(11 + R) + G + R = 50

Now plug our original second equation (R + 3 = G) into our third to get

(11 + R) + (R + 3) + R = 50

Combine and get

14 + 3R = 50 Subtract over the 14

3R = 36 Divide by 3

Orange Sodas = 12

Our new 3rd Equation is now: C + G + 12 = 50, subtract over 12 to get

C + G = 38

Plug either equation 1 or 2 into that one, I'll do 1

(8 + G) + G = 38

8 + 2G = 38

2G = 30

Grape Sodas = 15

Now our 3rd equation is C + 15 = 38, subtract over 15

Cola Sodas = 23

Orange = 12

Grape = 15

Cola = 23

12 + 15 + 23 = 50

7 0

3 years ago