The maximum units is 200 and , Total revenue is $8,000
<u>Step-by-step explanation:</u>
Here we have , A manufacturer finds that the revenue generated by selling of cortan commodity is given by function R(x)=80x-0.2x^ 2 , where he maximum reveremany should be manufactured to obtain this maximum units .Let's find out:
We have following function as 
. Let's differentiate this and equate it to zero to find value of x for which the function is maximum!
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Now , Value of function at x=200 is :
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Therefore , The maximum units is 200 and , Total revenue is $8,000
Answer:
x=6
Step-by-step explanation:
AB=BC
3x+3=2x+9
x=6
The functional equation of the line is f (x)=a*x+b
you have already a: -4 -->f (x)=-4 x+b
Now you can use the point (3;-3)
3 is the x-coordinate and -3 the f (x)-coordinate
--> -3 = -4*(3) + b Now you can solve it
-3 = -12+b (+12)
b = 9
ANSWER: f (x) = -4x + 9
Answer:
$25
Step-by-step explanation:
We know,
Monthly interest = (Principal × Interest rate) ÷ 12
Given,
Loan principal = $3,000
Interest rate = 10% = 0.10
Therefore, monthly interest = ($3,000 × 0.10) ÷ 12
Monthly interest = $300 ÷ 12
Monthly interest = $25
Therefore, the principal amount to be paid per month is = $(96.80 - 25) = $71.80.
So, Jamison will pay $25 as interest for the 36-month $3,000 loan.
Try, pls, this solution (see the attachment).
