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Brilliant_brown [7]
2 years ago
9

tossing a number cube numbered from 1 to 6 and getting an even number that is greater than or equal to 2

Mathematics
1 answer:
NNADVOKAT [17]2 years ago
8 0
3 because you take away the other numbers and leave the 1, 3 and 5 but I am not in college so.....Good luck
You might be interested in
(6x2 - 2x) + (5x-7)
Black_prince [1.1K]

Answer:

D. 6x2 + 3x - 7

Step-by-step explanation:

7 0
2 years ago
18. The Sahara Desert is the largest desert in the world. It covers 3,500,000 square miles. The Australian Desert is the second
ruslelena [56]
Solution:
3,500,000 - 2,030,000 = 1,470,000 square miles
Explanation:
Let's fully understand what this word problem is saying. Break it down.
The Sahara Desert is the largest desert in the world.
The Australian Desert is the second largest desert. 
This means that the Australian Desert has an area that is less than the Sahara desert. 
We are given the size of the Sahara, which is 3,500,000 square miles, but not the size of the Australian desert.The area of the Australian desert is less by 2,030,000 square miles.This is the amount we have to subtract from the area of the Sahara to find the size of the Australian desert:
3,500,000-2,030,000= 1,470,000 square miles. Hope this helps!
6 0
3 years ago
Asap, sorry the pics kinda blurry
Vadim26 [7]
Here is all the work with it

3 0
2 years ago
What is the slope of the line that passes through the points (2, –3) and (–2, 5)? 2 1/2 -1/2 -2
sergij07 [2.7K]

Answer: The slope is  -2.

Step-by-step explanation:

(2,-3)

(-2,5)

Using the two given points,  you can find the slope by finding the difference in the y coordinates and diving it by the difference in the x coordinates.

y coordinates:  -3 - 5= -8

x coordinates;  2-(-2) = 4  

Slope:  -8/ 4 = -2  

5 0
3 years ago
Given that (in picture)...
GuDViN [60]
<h3>Answer:  a = -3 and b = 5</h3>

=================================================

Work Shown:

Multiply top and bottom by \sqrt{2} to rationalize the denominator

\frac{10-\sqrt{18}}{\sqrt{2}}\\\\\frac{\sqrt{2}(10-\sqrt{18})}{\sqrt{2}*\sqrt{2}}\\\\\frac{\sqrt{2}*10-\sqrt{2}*\sqrt{18}}{\sqrt{2*2}}\\\\\frac{\sqrt{2}*10-\sqrt{2*18}}{\sqrt{4}}\\\\\frac{10\sqrt{2}-\sqrt{36}}{2}\\\\\frac{10\sqrt{2}-6}{2}\\\\\frac{-6+10\sqrt{2}}{2}\\\\\frac{2(-3+5\sqrt{2})}{2}\\\\-3+5\sqrt{2}\\\\

We end up with something in the form a+b\sqrt{2} where a = -3 and b = 5

7 0
2 years ago
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