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harkovskaia [24]
3 years ago
14

A school football team is selling raffle tickets As a fundraiser it cost them $155 to print the tickets and they would like to m

ake at least a $2500 profit how much money do they need to raise to cover the cost of the printing and meet their goals
Mathematics
1 answer:
sp2606 [1]3 years ago
8 0

Answer:

They need $2655 to raise to cover the costs of the printing and meet their goal.

Step-by-step explanation:

Consider the provided information.

As a fundraiser it cost them $155 to print the tickets and they would like to make at least a $2500 profit

Let x (in dollar) represents the fund raised.

The money spent on printing ticket is $155.

The profit they would like to make at least is $2500.

Therefore, the required inequality is:

x-155\geq 2500

Simplify the inequality.

x\geq 2500+155\\x\geq 2655

Therefore, they need $2655 to raise to cover the costs of the printing and meet their goal.

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Probability people where you at? 《brainlist if correct》
motikmotik
<h3>Answer:  5/9</h3>

As an approximate decimal, this is 0.5556 which converts to 55.56%

======================================================

Explanation:

Let's say there are 100 households (just for the sake of simplicity). We are told that 90% of them have answering machines. So that means 90 households have answering machines. In addition, 50 households have answering machines and call waiting. Those 50 households are part of the 90 mentioned previously.

We then select a house at random. Someone tells us (or we have some kind of prior knowledge) that whichever house is selected, they have an answering machine. We can ignore the 10 households that don't have an answering machine. Out of those 90 households, 50 have both features. So 50/90 = 5/9 is the probability of getting a household with both features.

The answer would be 1/2 or 50% if we didn't have the prior knowledge of the household having an answering machine. But with this prior knowledge, the conditions change and so does the probability.

----------------

You could also compute 0.50/0.90 to get the same answer.

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