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Leona [35]
4 years ago
6

Find the tangent of

Mathematics
1 answer:
Kamila [148]4 years ago
3 0
A² + b² = c²
RQ² + 60²  = 68²
RQ² = 68² - 60²
RQ² = 1024
RQ = √1024
RQ = 32

Tan(R) = opp/adj
Tan(R) = 60/32
Tan(R) = 15/8

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3 years ago
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PLEASE HELP ME: ASAP
VashaNatasha [74]

Ok so

Corresponding sides and angles are a pair of matching angles or sides that are in the same spot in two different shapes.

It would basically be a ratio (7:14)

My best help would be this

If two triangles are similar, then the ratio of the area of both triangles is proportional to the square of the ratio of their corresponding sides. This proves that the ratio of areas of two similar triangles is proportional to the squares of the corresponding sides of both the triangles.

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3 years ago
Express 2 1/3 + 3 1/6
Nutka1998 [239]
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7 0
4 years ago
The height, s, of a ball thrown straight down with initial speed 32 ft/sec from a cliff 48 feet high is s(t) = –16t2 – 32t + 48,
aalyn [17]
Remember that w<span>hen the ball hits the ground, s(t) = 0 
</span><span>So we have: -16t^2 - 32t + 48 = 0 </span>
<span>It's time to determine t = (-(-32) +/- sqrt((-32)^2 - 4(-16)(48))) / (2(-16)) </span>
<span>t = (32 +/- sqrt(1024 + 3072)) / (-32) </span>
<span>t = (32 +/- sqrt(4096)) / (-32) </span>
<span>t = (32 +/- 64) / (-32) </span>
<span>t = (48 or -32) / (-32) </span>
<span>t = -1.5 or 1 </span>
<span>Since a negative number doesn't make sense, so t =1</span>
<span>Keep in mind that velocity is the derivative of the height, therefore: </span>
<span>s'(t) = -32t - 32 </span>
<span>s'(t) = -32*1 - 32 </span>
<span>s'(t) = -32 - 32 </span>
<span>s'(t) = -64 </span>
<span>So the answer 64 feet per second dwn</span>
8 0
3 years ago
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