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2 years ago

Use an online to to estimate the cost for one year at a 4 year university and one year at a 2 year college in Texas.

Mathematics

1 answer:

mart [117]2 years ago

6 0

The answer is 50’ because the majority of the population is very high in Europe

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Use property to find sum pr product 8×51

aksik [14]

8 × 51 = 408

Eight times fifty-one equals four hundred eight

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2 years ago

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What is the distance between -12 and 15?

motikmotik

Answer:

Step-by-step explanation:

to get the distance, add -12 and 15 which gets you 27

8 0

2 years ago

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Which one is it please help meee

iragen [17]

Answer:

Matter in its gas state has the most thermal energy than when it is a solid or a liquid.

7 0

2 years ago

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A cable hangs between two poles of equal height and 35 feet apart. At a point on the ground directly under the cable and x feet

gayaneshka [121]

Answer:

293.38 pounds

Step-by-step explanation:

We are given that

Distance between poles=35 feet

$h(x)=10+0.1(x^{1.5})$

Weight of cable=10.4 per linear foot

We have to find the weight of the cable.

Differentiate w.r.t

$h'(x)=0.1(1.5)x^{0.5}=0.15x^{0.5}$

$s=2\int_{0}^{17.5}\sqrt{1+(h'(x))^2}dx$

$s=2\int_{0}^{17.5}\sqrt{1+(0.15x^{0.5})^2}dx$

$s=2\int_{0}^{17.5}\sqrt{1+0.0225x}dx$

Let $1+0.0225x=t$

$dx=\frac{1}{0.0225}dt$

$s=\frac{2}{0.0225}\int_{0}^{17.5}\sqrt{t}dt$

$s=\frac{2}{0.0225}\times\frac{2}{3}[t^{\frac{3}{2}}]^{17.5}_{0}$

$s=2\times \frac{2}{3\times0.0225}[(1+0.0255x)^{\frac{3}{2}]^{17.5}_{0}$

$s=\frac{4}{3\times 0.0225}((1+0.0225(17.5))^{\frac{3}{2}-1)$

s=28.21

Weight of cable= $28.21\times 10.4=293.38$ pound

8 0

2 years ago

YOU KNOW THAT THE SUM OF THE ANGLES IN A QUADRILATERAL IS 360 DECREES. HOW CAN THIS HELP YOU REMEMBER THAT THE SUM OF THE ANGLES

gtnhenbr [62]

Answer:

that can help because all you need to remember is that the sum of the angles in a triangle is half of the sum of the angles that add up in a quadrilateral.

5 0

1 year ago