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3 years ago

Chips numbered 1 through 80 are shuffled in a basket. One chip is randomly selected.

Mathematics

2 answers:

meriva3 years ago

8 0

1/16

multiples 15,30,45,60, and 75 making 5/80 then you simplify to 1/16

natka813 [3]3 years ago

7 0

Im taking the test, the answer is indeed 1/16

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Find x in the triangles

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Tan 32=9/x
x=14.4

cos29=x/7
x=6.12

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3 years ago

Rs = 8y + 4 , ST = 4y + 8 , and RT = 36 , find the value of y

Natasha_Volkova [10]

I assume that you meant RS and ST are segments of RT. If that is true then:

RS+ST=RT, using the values for these given...

8y+4+4y+8=36 combine like terms on left side

12y+12=36 subtract 12 from both sides

12y=24 divide both sides by 12

y=2

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3 years ago

Solve using standard algorithm 57.03+2.08

Rom4ik [11]

Answer:

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Step-by-step explanation:

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3 years ago

What is the difference? startfraction 2 x 5 over x squared minus 3 x endfraction minus startfraction 3 x 5 over x cubed minus 9

weeeeeb [17]

The difference of the expression $\frac{2x^5}{x^2 - 3x} - \frac{3x^5}{x^3 - 9x}$ is $\frac{2x^5(x + 3) - 3x^5}{x(x - 3)(x + 3)}$

<h3>How to determine the difference?</h3>

The expression is given as:

$\frac{2x^5}{x^2 - 3x} - \frac{3x^5}{x^3 - 9x}$

Factor the denominators of the expressions:

$\frac{2x^5}{x(x - 3)} - \frac{3x^5}{x(x^2 - 9)}$

Apply the difference of two squares to x² - 9

$\frac{2x^5}{x(x - 3)} - \frac{3x^5}{x(x - 3)(x + 3)}$

Take LCM

$\frac{2x^5(x + 3) - 3x^5}{x(x - 3)(x + 3)}$

Hence, the difference of the expression $\frac{2x^5}{x^2 - 3x} - \frac{3x^5}{x^3 - 9x}$ is $\frac{2x^5(x + 3) - 3x^5}{x(x - 3)(x + 3)}$

Read more about expressions at:

brainly.com/question/723406

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6 0

2 years ago

3×

In-s [12.5K]

Answer:

1. x = 39.67

2. x = 15

3. x = 49.29

4. x = -12.8

5. x = 96

6. x = 42

7. x = 36

8. x = 0

9. x = 78

Step-by-step explanation:

Just remember to always isolate the unknown. Here are the solutions to your problem. I will explain each step for the first for you to give you an idea how the others were worked out.

1. $\dfrac{3x}{7}-2 = 15$

Add 2 to both sides to get rid of -2 on the left side.

$\dfrac{3x}{7}-2+(2)=15+(2)///dfrac{3x}{7}=17$

Multiply both sides by 7 to get rid of 7 on the left side.

$\dfrac{3x}{7}\times 7 = 17\times 7\\\\3x = 119$

Divide both sides by 3 to get rid of 3 on the left side.

$\dfrac{3x}{3} = \dfrac{119}{3}\\\\x = 39.67$

You could also transpose everything by the x to the other side of the equation. Just remember that whatever OPERATION used on the original side, must be opposite on the other side. I'll use the second problem to show this.

$\dfrac{2x}{5}+1=7$

Transpose 1 on the left to the right. It is addition on the left, then it would be subtraction on the other side.

$\dfrac{2x}{5}+1=7\\\\\dfrac{2x}{5}=7-1\\\\\dfrac{2x}{5}=6$

Transpose 5 from the left side to the right. It is division on the left, then it would be multiplication on the right.

$\dfrac{2x}{5}=6\\\\2x=6\times 5\\\\2x=30$

Transpose 2 from the left side to the right. It is multiplication on the left, then it would be division on the right.

$2x=30\\\\x=\dfrac{30}{2}\\\\x=15$

Let's move on with the rest now.

$\dfrac{7x}{15}-1=22\\\\\dfrac{7x}{15}=22+1\\\\\dfrac{7x}{15}=23\\\\7x=23\times15\\\\7x=345\\\\x=\dfrac{345}{7}\\\\x=49.29$

$\dfrac{5x}{8}+10=2\\\\\dfrac{5x}{8}=2-10\\\\\dfrac{5x}{8}=-8\\\\5x=-8\times8\\\\5x=-64\\\\x=\dfrac{-64}{5}\\\\x=-12.8$

$\dfrac{x}{6}+4=20\\\\\dfrac{x}{6}=20-4\\\\\dfrac{x}{6}=16\\\\x=16\times6\\\\x=96$

$\dfrac{x}{3}-4=10\\\\\dfrac{x}{3}=10+4\\\\\dfrac{x}{3}=14\\\\x=3\times14\\\\x=42$

$\dfrac{x}{6}+2=8\\\\\dfrac{x}{6}=8-2\\\\\dfrac{x}{6}=6\\\\x=6\times6\\\\x=36$

$\dfrac{x}{9}+8=8\\\\\dfrac{x}{9}=8-8\\\\\dfrac{x}{9}=0\\\\x=0\times9\\\\x=0$

$\dfrac{x}{6}+7=20\\\\\dfrac{x}{6}=20-7\\\\\dfrac{x}{6}=13\\\\x=13\times6\\\\x=78$

6 0

3 years ago