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3 years ago

Is it true that the order when dividing three real numbers does not effect the answer?

Mathematics

2 answers:

Diano4ka-milaya [45]3 years ago

7 0

When dividing three real numbers the order can effect the answer.

Example:

8:4:2

1. 8:4:2=(8:4):2=2:2=1;

2. 8:4:2=8:(4:2)=8:2=4.

As you can see the results are different.

Answer: It is not true.

Ilia_Sergeevich [38]3 years ago

4 0

Yes, the order does matter. Real numbers include rational numbers, and whole numbers or integers are rational numbers. When dividing whole numbers, the order does matter.

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Craig went bowling with $25 to spend. he rented shoes for $5.00 and paid $4.00 for each game. What was the greatest number of ga

Anton [14]

Answer: A

Step-by-step explanation:

Given:

Budget = $25

Shoes rental = $5.00

Price per game = $4.00

To find the greatest number of games he played...

↓

First, subtract the rent for the shoes from the budget.

25 - 5 = 20

Second, divide the remaining money or budget by the price per game.

20 ÷ 4 = 5 (greatest number of games played)

Lastly, check if the expense is the same as the original amount of money.

5 (shoes) + 4(5) (number of games played)

5 + 20 = 25 (original amount of money)

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2 years ago

Simplify -3(2x-4)+8x-8

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-3(2x-4)+8x-8
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3 years ago

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9n is the answer to this question

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3 years ago

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You go shopping at a local department store with your friend and cousin. You buy one pair of jeans, four pairs of shorts, and tw

VashaNatasha [74]

Answer: Cost per pair of jeans = $ 20

Cost per pair of shorts = $12

Cost per shirt = $8

Step-by-step explanation:

Let x= cost per pair of jeans

y = Cost per pair of shorts

z= cost per shirt.

For you, total cost = x+4y+2z= 84

For your friend, total cost = 2x+y+3z=76

For cousin, total cost = x+2y+z= 52

Required system:

$x+4y+2z=84\ (i)\\ 2x+y+3z=76\ (ii)\\ x+2y+z=52\ (iii)$

from (i), $x=84-4y-2z$ (*)

put this in (ii) and (iii) we get

$2\left(84-4y-2z\right)+y+3z=76\\\Rightarrow\ -7y-z+168=76\ (iv)\\\\ 84-4y-2z+2y+z=52\\\Rightarrow\ -2y-z+84=52 \ (v)$

from (iv), $y=-\frac{z-92}{7}\ (vi)$

$\mathrm{Subsititute\:}y=-\frac{z-92}{7}\ \text{in}\ (v)$

$-2\left(-\frac{z-92}{7}\right)-z+84=52\\\\\Rightarrow\ -2\left(-\frac{z-92}{7}\right)-z=-32\\\\\Rightarrow\ -\frac{5z}{7}-\frac{184}{7}=-32\\\\\Rightarrow\ -5z-184=-224\\\\\Rightarrow\ -5z=-40\\\\\Rightarrow\ z=8$