The answer is D
Hope this helps
In hexadecimal/base-16, we have B₁₆ = 11, C₁₆ = 12, and D₁₆ = 13, so
4D₁₆ = 4 × 16¹ + 13 × 16⁰ = 77
and
BC2₁₆ = 11 × 16² + 12 × 16¹ + 2 × 16⁰ = 3010
Step-by-step explanation:
Use the quadratic formula to find the solutions.
−b±√b2−4(ac)2a-b±b2-4(ac)2a
Substitute the values a=9a=9, b=0b=0, and c=−81c=-81 into the quadratic formula and solve for xx.
x=±3x=±3
The final answer is the combination of both solutions.
x=3,−3x=3,-3
Answer:
Step-by-step explanation:
a = 4
b= 1
c = 2
d =2
Leftside of equation:
No. of H molecules = 4
No. of Cl molecules = 4
No. of O molecules = 4 *4 + 8 =16 + 8 = 24
No. of P molecules = 2
Right side of equation:
No. of H molecules = 4
No. of Cl molecules = 4
No. of O molecules = 2*5 + 2 *7 = 10 + 14 = 24
No. of P molecules = 2
