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solniwko [45]
3 years ago
9

I’d really appreciate the help

Mathematics
1 answer:
kiruha [24]3 years ago
6 0

Answer:

Step-by-step explanation:

a = 4

b= 1

c = 2

d =2

Leftside of equation:

No. of H molecules =  4

No. of Cl molecules =  4

No. of O molecules =  4  *4 + 8 =16 + 8 = 24

No. of P molecules = 2

Right side of equation:

No. of H molecules =  4

No. of Cl molecules =  4

No. of O molecules = 2*5 + 2 *7 = 10 + 14 = 24

No. of P molecules = 2

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Answer:

8x + 8

Step-by-step explanation:

There are 8x and the numbers equal 8.

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3 years ago
Pls help! i’m giving brainliest :)
fomenos
The answer is 2. Because every 2 cups pf flour is 1 half a sugar and, they are asking for 8 so thats 4 half cups of sugar, and if you mix another half with another half it would be 2 cups of sugar
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3 years ago
I'm really confused on this question..could anybody help?
DerKrebs [107]
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3 years ago
X/x-2 + x-1/x+1= -1<br> Can someone walk me through the steps of this problem? Much appreciated. :)
stealth61 [152]

Answer:

x = 0 or x = 1

Step-by-step explanation:

Given equation:

\dfrac{x}{x-2}+\dfrac{x-1}{x+1}=-1

Multiply the two denominators to get the same denominator:

Multiply the numerator of the first fraction by the denominator of the second fraction to get the new numerator of the first fraction.

Multiply the numerator of the second fraction by the denominator of the first fraction to get the new numerator of the second fraction.

\implies \dfrac{x(x+1)}{(x-2)(x+1)}+\dfrac{(x-2)(x-1)}{(x-2)(x+1)}=-1

Add the numerators and keep the denominator so that there is now one fraction:

\implies \dfrac{x(x+1)+(x-2)(x-1)}{(x-2)(x+1)}=-1

Simplify the numerator by expanding the brackets:

\implies \dfrac{x^2+x+x^2-3x+2}{(x-2)(x+1)}=-1

\implies \dfrac{2x^2-2x+2}{(x-2)(x+1)}=-1

Simplify the denominator by expanding the brackets:

\implies \dfrac{2x^2-2x+2}{x^2-x-2}=-1

Multiply both sides by the denominator of the left side:

\implies 2x^2-2x+2=-1(x^2-x-2)

Simplify and move everything to the left side:

\implies 2x^2-2x+2=-x^2+x+2

\implies 3x^2-3x=0

Factor:

\implies 3x(x-1)=0

Therefore:

\implies 3x=0 \implies x=0

\implies x-1=0 \implies x=1

Therefore, x = 0 or x = 1

8 0
2 years ago
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